Submission #706736

#TimeUsernameProblemLanguageResultExecution timeMemory
706736DennisTranRobots (APIO13_robots)C++17
0 / 100
42 ms105940 KiB
#pragma GCC optimize("O2") #pragma GCC target("avx,avx2,fma") #include <bits/stdc++.h> #define FOR(i, a, b) for (int i = (a); i <= (b); i++) #define FOD(i, a, b) for (int i = (a); i >= (b); i--) #define REP(i, n) for (int i = 0; i < (n); i++) #define ALL(x) (x).begin(), (x).end() #define TIME (1.0 * clock() / CLOCKS_PER_SEC) #define file(name) if (fopen(name".inp", "r")) { freopen(name".inp", "r", stdin); freopen(name".out", "w", stdout); } #define ii pair <int, int> #define fi first #define se second using namespace std; const int MAXN = 505; const int INF = 250000; int N, W, H, dp[MAXN][MAXN][10][10]; char a[MAXN][MAXN]; vector <ii> q[INF + 1]; ii end_pos[MAXN][MAXN][4]; inline bool inside(int x, int y) { return (x > 0 && y > 0 && x <= H && y <= W && a[x][y] != 'x'); } void Find_ending_points(void) { FOR(i, 1, H) FOR(j, 1, W) if (a[i][j] != 'x') { REP(k, 4) { ii pos = {i, j}; int d = (k + (a[i][j] == 'A') * 3 + (a[i][j] == 'C')) % 4; while (true) { if (d == 0) { if (inside(pos.first - 1, pos.second)) pos.first--; else break; } else if (d == 1) { if (inside(pos.first, pos.second + 1)) pos.second++; else break; } else if (d == 2) { if (inside(pos.first + 1, pos.second)) pos.first++; else break; } else { if (inside(pos.first, pos.second - 1)) pos.second--; else break; } if (~end_pos[pos.first][pos.second][d].first) { pos = end_pos[pos.first][pos.second][d]; break; } if (a[pos.first][pos.second] == 'A') d = (d + 3) % 4; if (a[pos.first][pos.second] == 'C') d = (d + 1) % 4; } end_pos[i][j][k] = pos; } } } void solve(void) { memset(dp, 0x3f3f3f3f, sizeof dp); cin >> N >> W >> H; FOR(i, 1, H) FOR(j, 1, W) { cin >> a[i][j]; if (a[i][j] >= '0' && a[i][j] <= '9') { dp[i][j][a[i][j] - '0'][a[i][j] - '0'] = 0; } REP(k, 4) end_pos[i][j][k] = {-1, -1}; } Find_ending_points(); REP(div, N) { FOR(l, 1, N - div) { int r = l + div; FOR(i, 1, H) FOR(j, 1, W) if (a[i][j] != 'x') for (int k = l; k < r; k++) dp[i][j][l][r] = min(dp[i][j][l][r], dp[i][j][l][k] + dp[i][j][k + 1][r]); } FOR(l, 1, N - div) { int r = l + div; FOR(i, 1, H) FOR(j, 1, W) if (a[i][j] != 'x' && dp[i][j][l][r] <= INF) q[dp[i][j][l][r]].emplace_back(i, j); FOR(i, 0, INF) if (q[i].size()) { for (auto tmp : q[i]) { int x = tmp.fi, y = tmp.se; if (dp[x][y][l][r] == i) { REP(k, 4) { int u = end_pos[x][y][k].first, v = end_pos[x][y][k].second; if (dp[u][v][l][r] > dp[x][y][l][r] + 1) { dp[u][v][l][r] = dp[x][y][l][r] + 1; q[dp[u][v][l][r]].emplace_back(u, v); } } } } q[i].clear(); } } } int ans = INT_MAX; FOR(i, 1, H) FOR(j, 1, W) ans = min(ans, dp[i][j][1][N]); cout << ans; } signed main(void) { ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr); //int T; cin >> T; while (T--) solve(); cerr << "Time elapsed: " << TIME << " s.\n"; return (0 ^ 0); }
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