This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <cmath>
#include <functional>
#include <fstream>
#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
#include <set>
#include <map>
#include <list>
#include <time.h>
#include <math.h>
#include <random>
#include <deque>
#include <queue>
#include <unordered_map>
#include <unordered_set>
#include <iomanip>
#include <cassert>
#include <bitset>
#include <sstream>
#include <chrono>
#include <cstring>
#include <numeric>
using namespace std;
typedef long long ll;
const int M = (int)1e9 + 7;
const int FACTN = 300000 + 7;
int add(int a, int b) {
a += b;
if (a >= M) return a - M;
if (a < 0) return a + M;
return a;
}
int mul(int a, int b) {
return a * (ll)b % M;
}
int add(int a, int b, int c) {
return add(add(a, b), c);
}
int mul(int a, int b, int c) {
return mul(mul(a, b), c);
}
int add(int a, int b, int c, int d) {
return add(add(a, b, c), d);
}
int mul(int a, int b, int c, int d) {
return mul(mul(a, b, c), d);
}
int add(int a, int b, int c, int d, int e) {
return add(add(a, b, c, d), e);
}
int mul(int a, int b, int c, int d, int e) {
return mul(mul(a, b, c, d), e);
}
int add(int a, int b, int c, int d, int e, int f) {
return add(add(a, b, c, d, e), f);
}
int mul(int a, int b, int c, int d, int e, int f) {
return mul(mul(a, b, c, d, e), f);
}
int add(int a, int b, int c, int d, int e, int f, int g) {
return add(add(a, b, c, d, e, f), g);
}
int mul(int a, int b, int c, int d, int e, int f, int g) {
return mul(mul(a, b, c, d, e, f), g);
}
int add(int a, int b, int c, int d, int e, int f, int g, int h) {
return add(add(a, b, c, d, e, f, g), h);
}
int mul(int a, int b, int c, int d, int e, int f, int g, int h) {
return mul(mul(a, b, c, d, e, f, g), h);
}
int pw(int a, int b) {
int r = 1;
while (b) {
if (b & 1) r = mul(r, a);
a = mul(a, a);
b /= 2;
}
return r;
}
int dv(int a, int b) {
return mul(a, pw(b, M - 2));
}
void addup(int& a, int b) {
a = add(a, b);
}
void mulup(int& a, int b) {
a = mul(a, b);
}
void dvup(int& a, int b) {
a = dv(a, b);
}
int fact[FACTN], ifact[FACTN];
void computeFACT() {
fact[0] = 1;
for (int i = 1; i < FACTN; i++) fact[i] = mul(fact[i - 1], i);
ifact[FACTN - 1] = dv(1, fact[FACTN - 1]);
for (int i = FACTN - 2; i >= 0; i--) ifact[i] = mul(ifact[i + 1], i + 1);
}
int getCOMB(int n, int k) {
return mul(fact[n], mul(ifact[k], ifact[n - k]));
}
const int N = 500 + 7;
int n;
int low[N], high[N];
vector<int> dp[N];
int lagrange(vector<pair<int, int>> have, int x)
{
for (auto& it : have)
{
if (it.first == x)
{
return it.second;
}
}
int y = 0;
for (int j = 0; j < (int)have.size(); j++)
{
int p = 1;
for (int m = 0; m < (int)have.size(); m++)
{
if (m != j)
{
mulup(p, dv(add(x, -have[m].first), add(have[j].first, -have[m].first)));
}
}
addup(y, mul(have[j].second, p));
}
return y;
}
int f(int x)
{
return add(mul(3, x, x, x), mul(x, x));
}
signed main()
{
#ifdef ONPC
FILE* stream;
freopen_s(&stream, "input.txt", "r", stdin);
#else
ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#endif
//{
// vector<pair<int, int>> lol;
// lol.push_back({ 1, f(1) });
// lol.push_back({ 2, f(2) });
// lol.push_back({ 3, f(3) });
// lol.push_back({ 4, f(4) });
// for (int i = 1; i <= 10; i++)
// {
// cout << i << " : " << f(i) << " vs " << lagrange(lol, i) << "\n";
// }
// exit(0);
//}
cin >> n;
for (int i = 1; i <= n; i++)
{
cin >> low[i] >> high[i];
assert(low[i] <= high[i]);
dp[i].resize(high[i] - low[i] + 1, 1);
}
for (int i = 1; i <= n; i++)
{
for (int j = 1; j < i; j++)
{
for (int y = low[i]; y <= high[i]; y++)
{
if (high[j] <= y - 1)
{
addup(dp[i][y - low[i]], dp[j].back());
}
else
{
if (low[j] <= y - 1)
{
addup(dp[i][y - low[i]], dp[j][y - 1 - low[j]]);
}
}
}
}
int make = min(high[i] - low[i] + 1, i);
vector<pair<int, int>> pts;
for (int d = 0; d < make; d++)
{
int pz = (int)dp[i].size() - 1 - d;
pts.push_back({ pz, dp[i][pz] });
}
for (int pz = 0; pz < (int)dp[i].size(); pz++)
{
//assert(dp[i][pz] == lagrange(pts, pz));
}
int cur = 0;
for (auto& it : dp[i])
{
addup(cur, it);
it = cur;
}
}
int sol = 0;
for (int i = 1; i <= n; i++)
{
addup(sol, dp[i].back());
}
cout << sol << "\n";
return 0;
}
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