Submission #700929

#	Time	Username	Problem	Language	Result	Execution time	Memory
700929		KiriLL1ca	Marriage questions (IZhO14_marriage)	C++17	88 / 100	1235 ms	1876 KiB

marriage

#include <bits/stdc++.h>
#define fr first
#define sc second
#define all(x) (x).begin(), (x).end()
#define pb push_back
#define endl '\n'
#define sz(x) (int)((x).size())
#define vec vector
#define pw(x) (1ll << x)

using namespace std;

template <typename T> inline bool umin (T &a, const T &b) { if (a > b) { a = b; return 1; } return 0; }
template <typename T> inline bool umax (T &a, const T &b) { if (a < b) { a = b; return 1; } return 0; }

typedef long double ld;
typedef long long ll;
typedef unsigned long long ull;
typedef pair <int, int> pii;

const int N = 3e4 + 2e3 + 10;
vec <int> g[N];
int used[N], mt[N], active[N], us = 0;

inline bool kuhn (int v) {
    if (used[v] == us) return 0;
    used[v] = us;
    for (auto &u : g[v]) if (active[u] && !~mt[u]) { mt[u] = v; return 1; }
    for (auto &u : g[v]) if (active[u] && kuhn(mt[u])) { mt[u] = v; return 1; }
    return 0;
}

inline void solve () {
    int n, m, k; cin >> n >> m >> k;
    for (int i = 0; i < k; ++i) {
        int u, v; cin >> u >> v; --u, --v;
        g[v].pb(u);
    }

    fill(mt, mt + N, -1);
    vec <int> girls;
    for (int i = 0; i < m; ++i) girls.pb(i);

    ll ans = 0;
    for (int l = 0, r = 0; l < n; ++l) {
        while (r < n) {
            active[r] = 1;
            while (sz(girls)) {
                ++us;
                int go = girls.back();
                if (kuhn(go)) girls.pop_back();
                else break;
            }
            if (!sz(girls)) break;
            ++r;
        }

        if (!sz(girls)) ans += n - r;

        if (~mt[l]) {
            girls.pb(mt[l]);
            mt[l] = -1;
            active[l] = 0;
        }
    }
    cout << ans << endl;
}

signed main () {
    ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
    #ifdef LOCAL
        freopen("input.txt", "r", stdin);
        freopen("output.txt", "w", stdout);
    #endif// LOCAL
    int t = 1; //cin >> t;
    while (t--) solve();
    return 0;
}

• Subtask 1: 88 / 100