Submission #6978

#TimeUsernameProblemLanguageResultExecution timeMemory
6978woqja125Split the sequence (APIO14_sequence)C++98
100 / 100
844 ms85852 KiB
#include<stdio.h> int dat[100001], s[100001]; long long dp[2][100001]; int p[210][100001]; int stk[100001], b; inline long long getY(long long *D, int x) { return D[x] - 1ll*s[x]*s[x]; } inline bool cmp(long long *D, int z) { int x, y; x = stk[b-1]; y = stk[b]; return (getY(D, y)-getY(D, x))*(s[y]-s[z]) >= (getY(D, z)-getY(D, y)) *(s[x]-s[y]); } int main() { int n, k; int i, j, l; scanf("%d%d", &n, &k); k++; for(i=1; i<=n; i++) { scanf("%d", &dat[i]); s[i] = s[i-1] + dat[i]; } for(i=0; i<=1; i++)for(j=0; j<=n; j++) dp[i][j]=-1; for(j=0; j<=n; j++) { dp[1][j] = 0; } for(i=2; i<=k; i++) { long long *D = dp[(i-1)%2]; b = -1; int x=1; stk[++b] = 0; stk[++b] = 1; for(l=2; l<=n; l++) { if(x>b) x = b; while(x < b && (getY(D, stk[x]) -getY(D, stk[x+1])) <= 1ll*(s[stk[x+1]] - s[stk[x]])*s[l] ) x++; dp[i%2][l] = D[stk[x]] - 1ll*s[stk[x]]*s[stk[x]] + 1ll*s[stk[x]]*s[l]; p[i][l] = stk[x]; while( b>x && cmp(D, l) ) b--; stk[++b] = l; } } printf("%lld\n", dp[k%2][n]); int x = n; for(int i=k; i>1; i--) { x = p[i][x]; printf("%d ", x); } return 0; }
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