Submission #686661

#	Time	Username	Problem	Language	Result	Execution time	Memory
686661		Alcabel	Xoractive (IZhO19_xoractive)	C++17	94 / 100	3 ms	464 KiB

Xoractive

#include <interactive.h>
#include <bits/stdc++.h>
using namespace std;
/*vector<int> unk;

int ask(int i) {
    return unk[i - 1];
}

vector<int> get_pairwise_xor(vector<int> a) {
    vector<int> res;
    for (const int& i : a) {
        for (const int& j : a) {
            res.emplace_back(unk[i - 1] ^ unk[j - 1]);
        }
    }
    sort(res.begin(), res.end());
    return res;
}
*/
vector<int> guess(int n) {
    vector<int> toAsk, x1, x2, ans(n);
    ans[0] = ask(1);
    unordered_map<int, int> idxOf;
    for (int bit = 31 - __builtin_clz(n); bit >= 0; --bit) {
        toAsk.clear();
        for (int i = 1; i < n; ++i) {
            if ((i & (1 << bit)) != 0) {
                toAsk.emplace_back(i + 1);
            }
        }
        x1 = get_pairwise_xor(toAsk);
        toAsk.emplace_back(1);
        x2 = get_pairwise_xor(toAsk);
        int ptr1 = (int)toAsk.size() - 1, ptr2 = (int)toAsk.size();
        while (ptr2 < (int)x2.size()) {
            if (ptr1 < (int)x1.size()) {
                if (x1[ptr1] == x2[ptr2]) {
                    ptr1 += 2, ptr2 += 2;
                } else if (x1[ptr1] < x2[ptr2]) {
                    ptr1 += 2;
                } else {
                    idxOf[x2[ptr2] ^ ans[0]] ^= (1 << bit);
                    ptr2 += 2;
                }
            } else {
                idxOf[x2[ptr2] ^ ans[0]] ^= (1 << bit);
                ptr2 += 2;
            }
        }
    }
    for (const auto& [num, idx] : idxOf) {
        ans[idx] = num;
    }
    return ans;
}
/*
void solve() {
    int n;
    cin >> n;
    unk.resize(n);
    for (int i = 0; i < n; ++i) {
        cin >> unk[i];
    }
    unk = guess(n);
    for (const int& x : unk) {
        cout << x << ' ';
    }
    cout << endl;
}

int main() {
    // ios_base::sync_with_stdio(0);
    // cin.tie(0);
    // cout.tie(0);

    int T = 1;
    // cin >> T;
    while (T--) {
        solve();
    }

    return 0;
}


*/

• Subtask 1: 0 / 6
• Subtask 2: 94 / 94