Submission #685502

#	Time	Username	Problem	Language	Result	Execution time	Memory
685502		opPO	Hedgehog Daniyar and Algorithms (IZhO19_sortbooks)	C++17	34 / 100	3095 ms	236144 KiB

sortbooks

#pragma GCC optimize("O3,unroll-loops")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

#define f first
#define s second
#define pb push_back
#define ld long double
#define sz(x) (int)x.size()
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define vec vector

using ll = long long;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using oset = tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update>;

mt19937_64 gen(chrono::steady_clock::now().time_since_epoch().count());
const ld eps = 1e-6;
const int mod = 1e9 + 7;
const int oo = 2e9;
const ll OO = 2e18;
const int N = 1e6 + 10;
int n, q, w[N], ans[4 * N];
vec<int> s[4 * N];

void merge(int v)
{
    vec<int> &a = s[2 * v + 1], &b = s[2 * v + 2];
    int n = sz(a), m = sz(b);
    int i = 0, j = 0;
    while (i < n || j < m)
    {
        if (i == n) s[v].pb(b[j++]);
        else if (j == m) s[v].pb(a[i++]);
        else
        {
            if (a[i] < b[j]) s[v].pb(a[i++]);
            else s[v].pb(b[j++]);
        }
    }
    ans[v] = max(ans[2 * v + 1], ans[2 * v + 2]);
    auto it = lower_bound(all(s[2 * v + 2]), s[2 * v + 1].back());
    if (it != s[2 * v + 2].begin())
    {
        --it;
        ans[v] = max(ans[v], s[2 * v + 1].back() + *it);
    }
}

void build(int v, int tl, int tr)
{
    if (tl == tr)
    {
        s[v].pb(w[tl]);
        return;
    }
    int m = (tl + tr) / 2;
    build(2 * v + 1, tl, m);
    build(2 * v + 2, m + 1, tr);
    merge(v);
}

void get(vec<int> &p, int l, int r, int v, int tl, int tr)
{
    if (tl > r || tr < l) return;
    if (tl >= l && tr <= r)
    {
        p.pb(v);
        return;
    }
    int m = (tl + tr) / 2;
    get(p, l, r, 2 * v + 1, tl, m);
    get(p, l, r, 2 * v + 2, m + 1, tr);
}

void solve()
{
    cin >> n >> q;
    for (int i = 1; i <= n; i++) cin >> w[i];
    build(0, 1, n);
    while (q--)
    {
        int l, r, k;
        cin >> l >> r >> k;
        vec<int> p;
        get(p, l, r, 0, 1, n);
        int mx = 0;
        vec<vec<int>> suff(sz(p), vec<int>(sz(p), -oo));
        for (int i = sz(p) - 1; i >= 0; i--)
        {
            mx = max(mx, ans[p[i]]);
            for (int j = 0; j < sz(p); j++)
            {
                int val = s[p[j]].back();
                auto it = lower_bound(all(s[p[i]]), val);
                if (it != s[p[i]].begin())
                {
                    --it;
                    suff[i][j] = *it;
                }
                if (i < sz(p) - 1) suff[i][j] = max(suff[i][j], suff[i + 1][j]);
            }
            if (i < sz(p) - 1) mx = max(mx, s[p[i]].back() + suff[i + 1][i]);
        }
        if (mx <= k) cout << 1;
        else cout << 0;
        cout << "\n";
    }
}

int32_t main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    solve();
    return 0;
}

• Subtask 1: 8 / 8
• Subtask 2: 9 / 9
• Subtask 3: 0 / 13
• Subtask 4: 17 / 17
• Subtask 5: 0 / 30
• Subtask 6: 0 / 23