# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
685212 | Farhan_HY | Grudanje (COCI19_grudanje) | C++14 | 0 ms | 0 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#define F first
#define S second
#define T int t; cin >> t; while(t--)
#define IOS ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
using namespace std;
const int N = 1e5 + 5;
const int M = 1e3 + 3;
const int inf = 1e18;
const int mod = 1e9 + 7;
int n, q, a[N];
pair<int, int> p[N], tree[30][4 * N];
string s;
pair<int, int> getMax(pair<int, int> p1, pair<int, int> p2) {
int mx = 0, mx2 = 0;
mx = max({p1.F, p1.S, p2.F, p2.S});
if (p1.F == mx) p1.F = 0;
else if (p1.S == mx) p1.S = 0;
else if (p2.F == mx) p2.F = 0;
else if (p2.S == mx) p2.S = 0;
mx2 = max({p1.F, p1.S, p2.F, p2.S});
return {mx1, mx2};
}
void build(int letter, int node, int tl, int tr) {
if (tr == tl) {
if (s[tr] == (letter + 'a')) tree[letter][node] = {a[tl], 0};
return;
}
int mid = (tl + tr) / 2;
build(letter, 2 * node, tl, mid);
build(letter, 2 * node + 1, mid + 1, tr);
tree[letter][node] = getMax(tree[letter][2 * node], tree[letter][2 * node + 1]);
}
pair<int, int> get(int letter, int node, int tl, int tr, int l, int r) {
if (tr < l || tl > r) return {0, 0};
if (l <= tl && tr <= r) return tree[letter][node];
int mid = (tl + tr) / 2;
pair<int, int> p1 = get(letter, 2 * node, tl, mid, l, r);
pair<int, int> p2 = get(letter, 2 * node + 1, mid + 1, tr, l, r);
return getMax(p1, p2);
}
main() {
IOS
cin >> s;
n = s.size();
s = '.' + s;
cin >> q;
for(int i = 1; i <= q; i++) cin >> p[i].F >> p[i].S;
sort(p, p + q + 1);
for(int i = 1; i <= n; i++) {
int x;
cin >> x;
a[x] = i;
}
int mx = 0;
for(int j = 0; j < 26; j++)
build(j, 1, 1, n);
for(int i = 1; i <= q; i++) {
for(int j = 0; j < 26; j++) {
int l = p[i].F, r = p[i].S;
int need = get(j, 1, 1, n, l, r).S;
mx = max(mx, need);
}
}
cout << mx << '\n';
}