Submission #685087

#	Time	Username	Problem	Language	Result	Execution time	Memory
685087		yhlas	Red-blue table (IZhO19_stones)	C++14	27 / 100	21 ms	1268 KiB

stones

#include <iostream>
//#include <algorithm>
//#include <math.h>
//#include <queue>
//#include <stack>
//#include <vector>
//#include <map>
//#include <set>
//#include <iomanip>
using namespace std;

//#include <ext/pb_ds/assoc_container.hpp>
//using namespace __gnu_pbds;
//typedef tree<ll,null_type,less<int>,rb_tree_tag,
//tree_order_statistics_node_update> indexed_set;

#define fbo find_by_order
#define ofk order_of_key

#define gg       500005
#define ll       long long
#define ull      unsigned ll
#define ld       long double
#define pii      pair<int,int>
#define pll      pair<ll,ll>
#define vi       vector<int>
#define vll      vector<ll>
#define stll     stack<ll>
#define qll      queue<ll>
#define pqll     priority_queue<ll>
#define pq       priority_queue

#define pb              push_back
#define ub              upper_bound
#define lb              lower_bound
#define issq(x)         (((ll)(sqrt((x))))*((ll)(sqrt((x))))==(x))
#define ff              first
#define ss              second
#define lg(r,n)         (int)(log2(n)/log2(r))

#define rev(v)              reverse(v.begin(),v.end())
#define srt(v)              sort(v.begin(),v.end())
#define srtr(v)             sort(v.rbegin(),v.rend());
#define all(v)              v.begin(),v.end()
#define allr(v)             v.rbegin(), v.rend()
#define mnv(v)              *min_element(v.begin(),v.end())
#define mxv(v)              *max_element(v.begin(),v.end())
#define countv(v,a)         count(v.begin(),v.end(),a)
#define sz(x)               (int)x.size()

int main()
{
    ios::sync_with_stdio(0);
    cin.tie(0);

    int _;
    cin >> _;
    while ( _--)
    {
        int n, m;
        cin >> n >> m;
        int mx = max(n, m), mn = min(n, m);
        cout << mx + (mn + 1) / 2 - 1 << '\n';
        for (int i = 1; i <= n; i++){
            char c = '-';
            if ( i > n / 2 + 1 ) c = '+';
            for (int j = 1; j <= m; j++){
                if ( mn == m and j > m / 2 + 1 ) c = '-';
                if ( mn == m and j <= m / 2 + 1 ) c = '+';
                cout << c;
            }
            cout << '\n';
        }
    }
}
//could_solve_myself:)

• Subtask 1: 17 / 17
• Subtask 2: 10 / 10
• Subtask 3: 0 / 16
• Subtask 4: 0 / 11
• Subtask 5: 0 / 15
• Subtask 6: 0 / 31