이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/*
#pragma comment(linker, "/stack:200000000")
#pragma GCC optimize("O3")
#pragma GCC target ("avx2")
#pragma GCC optimize("Ofast")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#pragma GCC optimize("unroll-loops")
*/
#include<bits/stdc++.h>
#define sz(v) (int)v.size()
#define ll long long
#define pb push_back
#define x first
#define y second
#define all(v) v.begin(), v.end()
#define rall(v) v.rbegin(), v.rend()
#define nl "\n"
using namespace std;
const int N = (int)1e5 + 7; // make sure this is right
const int M = (int)1e3 + 7;
const int inf = (int)2e9 + 7;
const ll INF = (ll)3e18 + 7;
const ll MOD = (ll)1e9 + 7; // make sure this is right
bool bit(int x, int i) {
return x >> i & 1;
}
int sum(int x, int y) {
x += y;
if(x >= MOD) x -= MOD;
return x;
}
pair<int, int> dir[] = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}};
int n, x[N], g[N], d[N];
int a[N], b[N];
ll p[N], w[N], t[8 * N];
void upd(int v, int tl, int tr, int i, ll x) {
if(tl == tr) {
t[v] = min(t[v], x);
return;
}
int mid = (tl + tr) >> 1;
if(i <= mid)
upd(v * 2, tl, mid, i, x);
else
upd(v * 2 + 1, mid + 1, tr, i, x);
t[v] = min(t[v * 2], t[v * 2 + 1]);
}
ll get(int v, int tl, int tr, int l, int r) {
if(tl >= l && tr <= r)
return t[v];
if(tl > r || l > tr || l > r)
return INF;
int mid = (tl + tr) >> 1;
return min(get(v * 2, tl, mid, l, r), get(v * 2 + 1, mid + 1, tr, l, r));
}
void compress() {
vector<ll> v;
for(int i = 1; i <= n; ++i) {
v.pb(p[i] - x[i]);
v.pb(p[i - 1] - x[i]);
}
sort(all(v));
v.erase(unique(all(v)), v.end());
for(int i = 1; i <= n; ++i) {
a[i] = lower_bound(all(v), p[i] - x[i]) - v.begin();
b[i] = lower_bound(all(v), p[i - 1] - x[i]) - v.begin();
}
}
void solve() {
cin >> n;
for(int i = 1; i <= n; ++i) {
cin >> x[i] >> g[i] >> d[i];
p[i] = p[i - 1] + d[i];
w[i] = w[i - 1] + g[i];
}
fill(t, t + 8 * N, INF);
compress();
ll ans = 0;
for(int i = 1; i <= n; ++i) {
upd(1, 1, n + n, b[i], w[i - 1]);
ans = max(ans, w[i] - get(1, 1, n + n, 1, a[i]));
}
cout << ans << "\n";
}
signed main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
int test = 1;
//cin >> test;
for(int i = 1; i <= test; ++i) {
//cout << "Case #" << i << ": ";
solve();
}
return 0;
}
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