Submission #682114

#TimeUsernameProblemLanguageResultExecution timeMemory
682114opPOMoney (IZhO17_money)C++17
45 / 100
1565 ms41572 KiB
#pragma GCC optimize("O3,unroll-loops") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; #define int long long #define f first #define s second #define pb push_back #define ld long double #define sz(x) (int)x.size() #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(), x.rend() #define vec vector using ll = long long; using pii = pair<int, int>; using pll = pair<ll, ll>; using oset = tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update>; mt19937_64 gen(chrono::steady_clock::now().time_since_epoch().count()); const ld eps = 1e-6; const int mod = 998244353; const int oo = 2e9; const ll OO = 2e18; const int N = 2e5 + 10; int n; vec<int> merge(vec<int> a, vec<int> b) { reverse(all(b)); for (int i = 0; i < sz(b) - 1; i++) if (b[i] > b[i + 1]) return {}; if (a.empty()) return b; for (int i = 0; i <= sz(a); i++) { int prv = (!i ? -1 : a[i - 1]); int nxt = (i == sz(a) ? OO : a[i]); if (b[0] >= prv && b.back() <= nxt) { vec<int> ret; for (int j = 0; j < i; j++) ret.pb(a[j]); for (int j = 0; j < sz(b); j++) ret.pb(b[j]); for (int j = i; j < sz(a); j++) ret.pb(a[j]); return ret; } } return a; } void solve() { cin >> n; vec<int> a(n + 1); for (int i = 1; i <= n; i++) cin >> a[i]; vec<int> dp(n + 1, OO); vec<vec<int>> best(n + 1); dp[0] = 0; for (int i = 1; i <= n; i++) { vec<int> b; for (int j = i; j >= 1; j--) { b.pb(a[j]); if (sz(merge(best[j - 1], b)) == i) { if (dp[j - 1] + 1 < dp[i]) { dp[i] = dp[j - 1] + 1; best[i] = merge(best[j - 1], b); } } } } cout << dp[n]; } int32_t main() { ios_base::sync_with_stdio(false); cin.tie(0); solve(); return 0; }
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