Submission #681934

# Submission time Handle Problem Language Result Execution time Memory
681934 2023-01-14T22:30:52 Z badont trapezoid (balkan11_trapezoid) C++17
72 / 100
170 ms 65536 KB
#include<bits/stdc++.h>
using namespace std;

void dbg_out() { cout << endl; }
template<typename Head, typename... Tail> void dbg_out(Head H, Tail... T) { cout << ' ' << H; dbg_out(T...); }

#ifdef LOCAL
#define debug(...) cout << "(" << #__VA_ARGS__ << "):", dbg_out(__VA_ARGS__)
#else
#define debug(...) "zzz"
#endif

using LL = long long;
using LD = long double;
using pii = pair<LL,LL>;

#define FOR(i, n) for(int i = 1; i<=n; i++)
#define F0R(i, n) for(int i = 0; i<n; i++)
#define all(x) x.begin(), x.end()
#define mp make_pair
#define pb push_back
#define f first
#define s second

template<typename T, typename = void> struct is_iterable : false_type {};
template<typename T> struct is_iterable<T, void_t<decltype(begin(declval<T>())),decltype(end(declval<T>()))>> : true_type {};
template<typename T> typename enable_if<is_iterable<T>::value&&!is_same<T, string>::value,ostream&>::type operator<<(ostream &cout, T const &v);
template<typename A, typename B> ostream& operator<<(ostream &cout, pair<A, B> const &p) { return cout << "(" << p.f << ", " << p.s << ")"; }
template<typename T> typename enable_if<is_iterable<T>::value&&!is_same<T, string>::value,ostream&>::type operator<<(ostream &cout, T const &v) {
	cout << "["; 
	for (auto it = v.begin(); it != v.end();) {
		cout << *it;
		if (++it != v.end()) cout << ", ";
	}
	return cout << "]";
}

//var 
LL T;

const int INF = 1e9;
const LL MOD = 30013;
struct mint {
    int x;
    mint() : x(0) {}
    template <class T> mint(T value) : x(value % MOD) { if (x < 0) x += MOD; }
    mint & operator+=(const mint &oth) { x += oth.x; if (x >= MOD) x -= MOD; return *this; }
    mint & operator-=(const mint &oth) { x -= oth.x; if (x < 0) x += MOD; return *this; }
    mint & operator*=(const mint &oth) { x = (long long) x * oth.x % MOD; return *this; }
    friend mint operator+(mint l, const mint &r) { return l += r; }
    friend mint operator-(mint l, const mint &r) { return l -= r; }
    friend mint operator*(mint l, const mint &r) { return l *= r; }
    mint & operator--() { if (--x == -1) x = MOD - 1; return *this; }
    mint & operator++() { if (++x == MOD) x = 0; return *this; }
    mint operator--(int) { mint temp = *this; --*this; return temp; }
    mint operator++(int) { mint temp = *this; ++*this; return temp; }
    mint operator-() const { return 0 - *this; }
    mint operator+() const { return *this; }
    friend bool operator==(const mint &l, const mint &r) { return l.x == r.x; }
    friend bool operator!=(const mint &l, const mint &r) { return l.x != r.x; }
    friend ostream & operator<<(ostream &out, const mint &a) { return out << a.x; }
    mint pow(long long e = MOD - 2) const {
        mint ans = 1, b = *this;
        while (e > 0) {
            if (e % 2 == 1) {
                ans *= b;
            }
            b *= b;
            e /= 2;
        }
        return ans;
    }
};

struct Info {
	int dp;
	mint ways;
	Info(int dp, mint ways) : dp(dp), ways(ways) {}
	Info(int dp) : dp(dp), ways(0) {}
};

Info max(const Info& a, const Info& b) {
	if (a.dp > b.dp) { return a; }
	if (b.dp > a.dp) { return b; }
	return Info(a.dp, a.ways + b.ways);
};
 
template <typename T, int SZ>
struct PST {
    struct Node {
        T val;
        int c[2];
        Node() : val(INF, 0) {
           
            c[0] = c[1] = 0;
        }
    };
    static const int LIM = 3e6;
    Node d[LIM];
    int nxt = 0;
    int copy(int t) { d[nxt] = d[t]; return nxt++; }
    T comb(const T& a, const T& b) { return max(a, b); }
    void pull(int c) { d[c].val = comb(d[d[c].c[0]].val, d[d[c].c[1]].val); }
    T query(int lo, int hi, int t, int l, int r) {
        if (lo >= r || hi <= l) return T(-INF, 0);
        if (lo <= l && r <= hi) return d[t].val;
        int m = (l + r) / 2;
        T lef = query(lo, hi, d[t].c[0], l, m);
        T rig = query(lo, hi, d[t].c[1], m, r);
        return comb(lef, rig);
    }
    int upd(int i, const T& v, int t, int l, int r) {
        int x = copy(t);
        if (r - l == 1) {
            d[x].val = max(d[x].val, v);
            return x;
        }
        int m = (l + r) / 2;
        if (i < m) {
            d[x].c[0] = upd(i, v, d[x].c[0], l, m);
        }else{
            d[x].c[1] = upd(i, v, d[x].c[1], m, r);
        }
        pull(x);
        return x;
    }
    int build(const vector<T>& a, int l, int r) {
        int c = nxt++;
        if (r - l == 1) {
            if (l < (int)a.size()) d[c].val = a[l];
            return c;
        }
        int m = (l + r) / 2;
        d[c].c[0] = build(a, l, m);
        d[c].c[1] = build(a, m, r);
        pull(c);
        return c;
    }
    vector<int> rts;
    void update_time(int i, const T& v) {
		//debug(rts);
        rts.pb(upd(i, v, rts.back(), 0, SZ));
    }
    void build(const vector<T>& a) {
        rts.pb(build(a, 0, SZ));
    }
    T query_time(int ti, int lo, int hi) {
        return query(lo, hi, rts[ti], 0, SZ);
    }
};
PST<Info, 1 << 17> pst;

void solve() {
	int n;
	cin >> n;

	vector<array<int, 4>> a(n);
	for (auto& [x, y, z, d] : a)
		cin >> x >> y >> z >> d;

	vector<LL> a_ricky, b_ricky;
	for (auto [x, y, z, d] : a) {
		a_ricky.pb(x);
		a_ricky.pb(y);
		b_ricky.pb(z);
		b_ricky.pb(d);
	}

	sort(all(a_ricky));
	sort(all(b_ricky));

	a_ricky.erase(unique(all(a_ricky)), a_ricky.end());
	b_ricky.erase(unique(all(b_ricky)), b_ricky.end());

	auto get_a = [&](const LL& g) -> LL {
		return lower_bound(all(a_ricky), g) - a_ricky.begin() + 1;
	};
	auto get_b = [&](const LL& g) -> LL {
		return lower_bound(all(b_ricky), g) - b_ricky.begin() + 1;
	};

	int A = (int)a_ricky.size();
	int B = (int)b_ricky.size();
	vector sweep(A + 1, vector<array<LL, 3>>());

	for (auto& [x, y, z, d] : a) {
		sweep[get_a(y)].pb({get_a(x), get_b(z), get_b(d)});
	}

	//debug(sweep);
	vector<Info> init(B + 1, Info(-INF, 0)); init[0] = Info(0, 1);
	pst.build(init);
	//vector<node<Info>*> roots = {(tree.build(init))};

	Info ans(-INF, 0);
	vector<int> time_of = {0};
	FOR (i, A) {
		
		for (auto& [l, x, y] : sweep[i]) {
			Info trans = pst.query_time(time_of[l - 1], 0, x);
			Info next = Info(trans.dp + 1, trans.ways);
			ans = max(ans, next);
			pst.update_time(y, next);
		}
		time_of.pb((int)pst.rts.size() - 1);
	}

	cout << ans.dp << " " << ans.ways << "\n";
}

int main() {
	ios_base::sync_with_stdio(0); 
	cin.tie(0);

	T = 1;
	//cin >> T;
	FOR(t, T)
		solve();

	cout.flush();
	return 0;
}

 
# Verdict Execution time Memory Grader output
1 Correct 23 ms 47188 KB Output is correct
2 Correct 22 ms 47288 KB Output is correct
3 Correct 22 ms 47316 KB Output is correct
4 Correct 23 ms 47428 KB Output is correct
5 Correct 25 ms 47572 KB Output is correct
6 Correct 26 ms 47696 KB Output is correct
7 Correct 30 ms 47828 KB Output is correct
8 Correct 30 ms 48132 KB Output is correct
9 Correct 36 ms 48856 KB Output is correct
10 Correct 51 ms 50496 KB Output is correct
11 Correct 55 ms 51212 KB Output is correct
12 Correct 94 ms 55232 KB Output is correct
13 Correct 119 ms 57496 KB Output is correct
14 Incorrect 129 ms 60592 KB Output isn't correct
15 Partially correct 151 ms 61476 KB Partially correct
16 Incorrect 154 ms 62328 KB Output isn't correct
17 Incorrect 158 ms 63208 KB Output isn't correct
18 Correct 143 ms 64044 KB Output is correct
19 Incorrect 170 ms 64864 KB Output isn't correct
20 Incorrect 167 ms 65536 KB Output isn't correct