Submission #681108

#	TimeUTC-0	Username	Problem	Language	Result	Execution time	Memory
681108	2023-01-12 11:05:02	Cross_Ratio	Nuclearia (CEOI15_nuclearia)	C++14	15 / 100	1099 ms	80712 KiB

nuclearia

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#include <bits/stdc++.h>
#pragma GCC optimize("O3")
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
using namespace std;
long long int A[2500002][2];
long long int B[2500002][2];
array<long long int, 4> C[200005];
signed main() {
    cin.sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    int W, H;
    cin >> W >> H;
    int i, j;
    int N;
    cin >> N;
    for(i=0;i<N;i++) {
        cin >> C[i][0] >> C[i][1] >> C[i][2] >> C[i][3];
        C[i][0]--, C[i][1]--;
        for(j=0;j<W;j++) {
            for(register int k = 0; k < H; k++) {
                A[j][k] += max(0LL, C[i][2] - max(abs(j-C[i][0]),abs(k-C[i][1])) * C[i][3]);
            }
        }
    }
    for(i=0;i<W;i++) {
        for(j=0;j<H;j++) {
            B[i][j] = (i?B[i-1][j]:0) + (j?B[i][j-1]:0) - ((long long int)i*j?B[i-1][j-1]:0) + A[i][j];
        }
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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Compilation message (stderr)

nuclearia.cpp: In function 'int main()':
nuclearia.cpp:29:76: warning: '*' in boolean context, suggest '&&' instead [-Wint-in-bool-context]
   29 |             B[i][j] = (i?B[i-1][j]:0) + (j?B[i][j-1]:0) - ((long long int)i*j?B[i-1][j-1]:0) + A[i][j];
      |                                                            ~~~~~~~~~~~~~~~~^~
nuclearia.cpp:38:77: warning: '*' in boolean context, suggest '&&' instead [-Wint-in-bool-context]
   38 |         long long int val = B[c][d] - (a?B[a-1][d]:0) - (b?B[c][b-1]:0) + (a*b?B[a-1][b-1]:0);
      |                                                                            ~^~

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