Submission #679440

#	Time	Username	Problem	Language	Result	Execution time	Memory
679440		anhduc2701	Dango Maker (JOI18_dango_maker)	C++17	33 / 100	15 ms	39120 KiB

dango_maker

/*
#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimize("unroll-loops")
*/
#include<bits/stdc++.h>
#define all(x) x.begin(), x.end()
#define len(x) ll(x.size())
#define eb emplace_back
#define PI 3.14159265359
#define fi first
#define se second
#define mp make_pair
#define pb push_back
#define MIN(v) *min_element(all(v))
#define MAX(v) *max_element(all(v))
#define BIT(x,i) (1&((x)>>(i)))
#define MASK(x) (1LL<<(x))
#define task "tnc"  
using namespace std;
typedef long long ll;
const ll INF=1e18;
const int maxn=1e6+5;
const int mod=1e9+7;
const int mo=998244353;
using pi=pair<ll,ll>;
using vi=vector<ll>;
using pii=pair<pair<ll,ll>,ll>;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
int n,m;
char a[3005][3005];
int dp[2][3005][3005];
bool check[2][3005][2005];
int check1(int i,int j){
	return a[i][j-2]=='R' && a[i][j-1]=='G' && a[i][j]=='W';
}
int check2(int i,int j){
	return a[i-2][j]=='R' && a[i-1][j]=='G' && a[i][j]=='W';
}
signed main()
{
	cin.tie(0),cout.tie(0)->sync_with_stdio(0);
    //freopen(task".inp" , "r" , stdin);
    //freopen(task".out" , "w" , stdout);
   	cin>>n>>m;
   	for(int i=1;i<=n;i++){
   		for(int j=1;j<=m;j++){
   			cin>>a[i][j];
   		}
   	} 
   	for(int i=1;i<=n;i++){
   		for(int j=3;j<=m;j++){
   			check[0][i][j]=check1(i,j);
   		}
   	}
   	for(int i=3;i<=n;i++){
   		for(int j=1;j<=m;j++){
   			check[1][i][j]=check2(i,j);
   		}
   	}
   	for(int i=1;i<=n;i++){
   		for(int j=1;j<=m;j++){
   			dp[1][i][j]=dp[1][i-1][j+1]+check[1][i][j];
   			if(i>3)dp[1][i][j]=max(dp[1][i][j],dp[0][i-3][j+3]+check[1][i][j]);
   			dp[0][i][j]=max(dp[1][i][j],dp[0][i-1][j+1]+check[0][i][j]);
   		}
   	}
   	int ans=0;
   	for(int i=1;i<=n;i++){
   		for(int j=1;j<=m;j++){
   			if((j==1|| i==n)){
   				ans+=dp[0][i][j];
   			}
   		}
   	}
   	cout<<ans<<" ";
    return 0;
}

• Subtask 1: 13 / 13
• Subtask 2: 20 / 20
• Subtask 3: 0 / 67