Submission #679438

#TimeUsernameProblemLanguageResultExecution timeMemory
679438kussssoCommuter Pass (JOI18_commuter_pass)C++17
31 / 100
471 ms31880 KiB
#include<bits/stdc++.h> using namespace std; using ll = long long; #define int long long const int N = 1e5 + 5; const ll inf = 1e18; typedef pair<int, ll> edge; #define fi first #define se second struct Node { ll fu; int u; bool hu, hv; bool operator < (const Node& oth) const { return fu > oth.fu; } }; int n, m; int S, T, U, V; ll f[N][2][2], ans; vector<edge> g[N]; vector<int> pa[N]; vector<ll> du, dv, ds, dt; vector<ll> Dij (int st) { for (int i = 1; i <= n; i++) pa[i].clear(); vector<ll> d(n + 1, inf); d[st] = 0; priority_queue<pair<ll, int>> pq; pq.push({0, st}); while (!pq.empty()) { ll du = -pq.top().fi; int u = pq.top().se; pq.pop(); if (d[u] != du) continue; for (auto e : g[u]) { int v = e.fi; ll w = e.se; if (d[v] > d[u] + w) { d[v] = d[u] + w; pq.push({-d[v], v}); pa[v] = {u}; } else if (d[v] == d[u] + w) { pa[v].push_back(u); } } } return d; } ll dp1[N], dp2[N]; bool vis[N]; signed main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> n >> m >> S >> T >> U >> V; for (int i = 0; i < m; i++) { int u, v, c; cin >> u >> v >> c; g[u].push_back({v, c}); g[v].push_back({u, c}); } du = Dij(U); dv = Dij(V); ds = Dij(S); dt = Dij(T); ans = du[V]; for (int i = 0; i <= n; i++) { for (int j = 0; j < 2; j++) { for (int x = 0; x < 2; x++) { f[i][j][x] = inf; } } } priority_queue<Node> pq; pq.push({0, S, 0, 0}); f[S][0][0] = 0; while (!pq.empty()) { auto [fu, u, hu, hv] = pq.top(); pq.pop(); if (fu != f[u][hu][hv]) continue; bool nhu = hu | (u == U); bool nhv = hv | (u == V); if (!nhu) { if (f[u][1][nhv] > fu + du[u]) { f[u][1][nhv] = fu + du[u]; pq.push({f[u][1][nhv], u, 1, nhv}); } } if (!nhv) { if (f[u][nhu][1] > fu + dv[u]) { f[u][nhu][1] = fu + dv[u]; pq.push({f[u][nhu][1], u, nhu, 1}); } } if (!nhu && !nhv) { if (f[u][1][1] > fu + du[u] + dv[u]) { f[u][1][1] = fu + du[u] + dv[u]; pq.push({f[u][1][1], u, 1, 1}); } } for (int v : pa[u]) { if (f[v][nhu][nhv] > fu) { f[v][nhu][nhv] = fu; pq.push({f[v][nhu][nhv], v, nhu, nhv}); } } } ans = min(ans, f[T][1][1]); cout << ans; return 0; }
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