Submission #678402

#TimeUTC-0UsernameProblemLanguageResultExecution timeMemory
6784022023-01-05 18:01:19Ahmed57Bootfall (IZhO17_bootfall)C++17
100 / 100
514 ms6136 KiB
/*
IZhO 17-bootfall
Do knapsack for the initial n items. We will store count[i] = how many subsets have sum i, mod some big prime.
When we want to remove 1 item, we have to reverse the knapsack and then revert back to the initial state.
At the end, we need to check how many differences appear in all of the n removals, and this can be counted with a frequency array.
*/
#include<bits/stdc++.h>
#define god dimasi5eks
#pragma GCC optimize("O3")
#define fi first
#define se second
#define pb push_back
#define pf push_front
#define mod 1000000007
#define dancila 3.14159265359
#define eps 1e-9
using namespace std;
typedef long long ll;
int add(int a, int b)
{
ll x = a+b;
if(x >= mod)
 
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