This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#define here cerr<<"===========================================\n"
#define dbg(x) cerr<<#x<<": "<<x<<endl;
#include "bits/stdc++.h"
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
#define ld double
#define ll int
#define llinf 100000000000000000LL // 10^17
#define pb push_back
#define popb pop_back
#define fi first
#define sc second
#define endl '\n'
#define pll pair<ll,ll>
#define pld pair<ld,ld>
#define sz(a) (ll)(a.size())
#define all(a) a.begin(),a.end()
#define ceri(a,l,r) {cerr<<#a<<": ";for(ll i_ = l;i_<=r;i_++) cerr<<a[i_]<< " ";cerr<<endl;}
#define cer(a) {cerr<<#a<<": ";for(ll x_ : a) cerr<<x_<< " ";cerr<<endl;}
#define daj_mi_malo_vremena ios_base::sync_with_stdio(false);cerr.tie(0);cout.tie(0);cin.tie(0);
using namespace std;
using namespace __gnu_pbds;
typedef tree<int,null_type,less_equal<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_multiset;
#define maxn 400005
struct tupl{
ll x,y,sum,id;
} v[maxn];
ll n,q;
pll a[maxn];
bool ok[maxn];
bool cmp(pll x,pll y){return x.fi+x.sc<y.fi+y.sc;}
bool cmp2(tupl x,tupl y){return x.sum<y.sum;}
bool cmp3(tupl x,tupl y){
if(x.x!=y.x) return x.x<y.x;
return x.y<y.y;
}
ll ans[maxn];
void tc(){
cin >> n >> q;
for(ll i = 1;i<=n;i++) cin >> a[i].fi >> a[i].sc;
for(ll i = 1;i<=q;i++) cin >> v[i].x >> v[i].y >> v[i].sum;
for(ll i = 1;i<=q;i++) v[i].id = i;
sort(a+1,a+1+n,cmp);
sort(v+1,v+1+q,cmp2);
ll k = n;
ordered_multiset sx,sy;
for(ll j = q;j>=1;j--){
if(v[j].x+v[j].y>=v[j].sum){
ok[v[j].id] = 1;
continue;
}
while(k>=1&&a[k].fi+a[k].sc>=v[j].sum){
sx.insert(a[k].fi); sy.insert(a[k].sc);
k--;
}
ans[v[j].id] = sz(sx) - sx.order_of_key(v[j].x) - sy.order_of_key(v[j].y);
}
sort(v+1,v+1+q,cmp3);
sort(a+1,a+1+n);
sy.clear();
k = n;
for(ll i = q;i>=1;i--){
if(!ok[v[i].id]) continue;
while(k>=1&&a[k].fi>=v[i].x){
sy.insert(a[k].sc);
k--;
}
ans[v[i].id] = sz(sy) - sy.order_of_key(v[i].y);
}
for(ll i = 1;i<=q;i++) cout<<ans[i]<<endl;
}
int main(){
daj_mi_malo_vremena
int t; t = 1;
while(t--){
tc();
}
return 0;
}
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