Submission #675986

#	Time	Username	Problem	Language	Result	Execution time	Memory
675986		urosk	Two Antennas (JOI19_antennas)	C++14	0 / 100	87 ms	65128 KiB

antennas

#define here cerr<<"===========================================\n"
#define dbg(x) cerr<<#x<<": "<<x<<endl;
#include "bits/stdc++.h"
//#include <ext/pb_ds/tree_policy.hpp>
//#include <ext/pb_ds/assoc_container.hpp>
#define ld double
#define ll long long
#define llinf 100000000000000000LL // 10^17
#define pb push_back
#define popb pop_back
#define fi first
#define sc second
#define endl '\n'
#define pll pair<ll,ll>
#define pld pair<ld,ld>
#define sz(a) (ll)(a.size())
#define all(a) a.begin(),a.end()
#define ceri(a,l,r) {cerr<<#a<<": ";for(ll i_ = l;i_<=r;i_++) cerr<<a[i_]<< " ";cerr<<endl;}
#define cer(a) {cerr<<#a<<": ";for(ll x_ : a) cerr<<x_<< " ";cerr<<endl;}

#define daj_mi_malo_vremena ios_base::sync_with_stdio(false);cerr.tie(0);cout.tie(0);cin.tie(0);

using namespace std;
//using namespace __gnu_pbds;
/*
ll add(ll x,ll y){
    x+=y;
    if(x<0){
        x%=mod;
        x+=mod;
    }else{
        if(x>=mod) x%=mod;
    }
    return x;
}
ll mul(ll a,ll b){
	ll ans = (a*b)%mod;
	if(ans<0) ans+=mod;
	return ans;
}
typedef tree<int,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_set;
typedef tree<int,null_type,less_equal<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_multiset;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
ll rnd(ll l,ll r){
    return uniform_int_distribution<ll>(l,r)(rng);
}
*/
#define maxn 200005
ll n,q;
ll h[maxn],a[maxn],b[maxn];
pll v[maxn];
ll t[4*maxn],t2[4*maxn],lazy[4*maxn];
ll ans[maxn];
vector<pll> kv[maxn];
vector<ll> add[maxn],del[maxn];
ll ls[maxn],rs[maxn],tsz = 0,root = 0;
void init(ll &v,ll tl,ll tr){
    v = ++tsz;
    t[v] = t2[v] = lazy[v] = -llinf;
    if(tl==tr) return;
    ll mid = (tl+tr)/2;
    init(ls[v],tl,mid);
    init(rs[v],mid+1,tr);
}
void upd2(ll v,ll tl,ll tr,ll i,ll x){
    if(tl==tr){t2[v] = x;return;}
    ll mid = (tl+tr)/2;
    if(i<=mid) upd2(ls[v],tl,mid,i,x);
    else upd2(rs[v],mid+1,tr,i,x);
    t2[v] = max(t2[ls[v]],t2[rs[v]]);
}
void upd(ll v,ll x){
    t[v] = max(t[v],t2[v]+x);
    lazy[v] = max(lazy[v],x);
}
void push(ll v){
    if(lazy[v]!=-llinf){
        upd(ls[v],lazy[v]);
        upd(rs[v],lazy[v]);
        lazy[v] = -llinf;
    }
}
void upd(ll v,ll tl,ll tr,ll l,ll r,ll x){
    if(l>r) return;
    if(tl==l&&tr==r){upd(v,x);return;}
    push(v);
    ll mid = (tl+tr)/2;
    upd(ls[v],tl,mid,l,min(mid,r),x);
    upd(rs[v],mid+1,tr,max(mid+1,l),r,x);
    t[v] = max(t[ls[v]],t[rs[v]]);
}
ll get(ll v,ll tl,ll tr,ll l,ll r){
    if(l>r) return -llinf;
    if(tl==l&&tr==r) return t[v];
    push(v);
    ll mid = (tl+tr)/2;
    return max(get(ls[v],tl,mid,l,min(mid,r)),get(rs[v],mid+1,tr,max(mid+1,l),r));
}
void reshi(){
    init(root,1,n);
    for(ll i = 1;i<=n;i++){
        ll l = min(n,i+a[i]);
        ll r = min(n,i+b[i]);
        add[l].pb(i);
        del[r].pb(i);
        for(ll j : add[i]) upd2(root,1,n,j,h[j]);
        upd(root,1,n,max(1LL,i-b[i]),max(1LL,i-a[i]),-h[i]);
        for(pll p : kv[i]) ans[p.sc] = max(ans[p.sc],get(root,1,n,p.fi,i));
        for(ll j : del[i]) upd2(root,1,n,j,-llinf);
        add[i].clear();
        del[i].clear();
    }
    for(ll i = 0;i<=tsz;i++) rs[i] = ls[i] = 0;
    root = tsz = 0;
}
void tc(){
    cin >> n;
    for(ll i = 1;i<=n;i++) cin >> h[i] >> a[i] >> b[i];
    cin >> q;
    for(ll i = 1;i<=q;i++) cin >> v[i].fi >> v[i].sc;
    for(ll i = 1;i<=q;i++) kv[v[i].sc].pb({v[i].fi,i});
    for(ll i = 1;i<=q;i++) ans[i] = -llinf;
    reshi();
    for(ll i = 1;i<=n;i++) h[i] = -h[i];
    reshi();
    for(ll i = 1;i<=q;i++) if(ans[i]<=-llinf/2) ans[i] = -1;
    for(ll i = 1;i<=q;i++) cout<<ans[i]<<endl;
}
int main(){
	daj_mi_malo_vremena
    int t; t = 1;
    while(t--){
        tc();
    }
	return 0;
}

• Subtask 1: 0 / 2
• Subtask 2: 0 / 11
• Subtask 3: 0 / 22
• Subtask 4: 0 / 65