Submission #675788

#	Time	Username	Problem	Language	Result	Execution time	Memory
675788		Victor	Osumnjičeni (COCI21_osumnjiceni)	C++17	0 / 110	109 ms	32180 KiB

Main

#pragma GCC target ("avx,avx2,fma")
#pragma GCC optimize ("Ofast,inline") // O1 - O2 - O3 - Os - Ofast
#pragma GCC optimize ("unroll-loops")
#include <bits/stdc++.h>

using namespace std;

#define rep(i, a, b) for (int i = (a); i < (b); ++i)
#define per(i, a, b) for (int i = (b) - 1; i >= (a); --i)
#define trav(a, x) for (auto &a : x)

#define all(x) x.begin(), x.end()
#define sz(x) (int)x.size()
#define pb push_back
#define debug(x) cout<<#x<<" = "<<x<<endl

#define umap unordered_map
#define uset unordered_set

typedef pair<int, int> ii;
typedef pair<int, ii> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<vi> vvi;

typedef long long ll;
typedef pair<ll,ll> pll;
typedef vector<ll> vll;
typedef vector<pll> vpll;

const int INF = 1'000'000'007;

const int inf = 1e9;
struct Node {
	Node *l = 0, *r = 0;
	int lo, hi, mset = inf, madd = 0, val = inf;
	Node(int lo,int hi):lo(lo),hi(hi){} // Large interval of -inf
	Node(vi& v, int lo, int hi) : lo(lo), hi(hi) {
		if (lo + 1 < hi) {
			int mid = lo + (hi - lo)/2;
			l = new Node(v, lo, mid); r = new Node(v, mid, hi);
			val = min(l->val, r->val);
		}
		else val = v[lo];
	}
	int query(int L, int R) {
		if (R <= lo || hi <= L) return inf;
		if (L <= lo && hi <= R) return val;
		push();
		return min(l->query(L, R), r->query(L, R));
	}
	void set(int L, int R, int x) {
		if (R <= lo || hi <= L) return;
		if (L <= lo && hi <= R) mset = val = x, madd = 0;
		else {
			push(), l->set(L, R, x), r->set(L, R, x);
			val = min(l->val, r->val);
		}
	}
	void add(int L, int R, int x) {
		if (R <= lo || hi <= L) return;
		if (L <= lo && hi <= R) {
			if (mset != inf) mset += x;
			else madd += x;
			val += x;
		}
		else {
			push(), l->add(L, R, x), r->add(L, R, x);
			val = min(l->val, r->val);
		}
	}
	void push() {
		if (!l) {
			int mid = lo + (hi - lo)/2;
			l = new Node(lo, mid); r = new Node(mid, hi);
		}
		if (mset != inf)
			l->set(lo,hi,mset), r->set(lo,hi,mset), mset = inf;
		else if (madd)
			l->add(lo,hi,madd), r->add(lo,hi,madd), madd = 0;
	}
};

int jmp[18][200005];

int main() {
    cin.tie(0)->sync_with_stdio(0);
    cin.exceptions(cin.failbit);

    int n,q;
    int heights[200005][2];
    cin>>n;

	/*set<int> unique_heights;
    rep(i,0,n) rep(j,0,2) cin>>heights[i][j],unique_heights.insert(heights[i][j]);
	umap<int,int> compress;
	int cnt=0;
	trav(height,unique_heights) compress[height]=cnt++;
	rep(i,0,n) rep(j,0,2) heights[i][j]=compress[heights[i][j]];*/
	

    Node segtree(0,INF);
    per(i,0,n) {
        jmp[0][i]=segtree.query(heights[i][0],heights[i][1]+1);
        if(i+1!=n) jmp[0][i]=min(jmp[0][i],jmp[0][i+1]);
        //debug(jmp[0][i])<<endl;
        segtree.set(heights[i][0],heights[i][1]+1,i);
    }

    rep(j,1,18) rep(i,0,n) {
        if(jmp[j-1][i]>=inf) jmp[j][i]=inf;
        else jmp[j][i]=jmp[j-1][jmp[j-1][i]];
    }

    cin>>q;
    while(q--) {
        int lo,hi;
        cin>>lo>>hi;
        --lo;
        int cnt=1;
        //cout<<"lo = "<<lo<<" hi = "<<hi<<endl;
        per(j,0,18) {
            //cout<<"j = "<<j<<" lo = "<<lo<<" jmp = "<<jmp[j][lo]<<endl;
            if(jmp[j][lo]<hi) {
                cnt+=1<<j;
                lo=jmp[j][lo];
            }
        }
        cout<<cnt<<endl;
    }
    _Exit(0);
    return 0;
}

Compilation message (stderr)

Main.cpp: In function 'int main()':
Main.cpp:104:59: warning: ''target_mem_ref' not supported by dump_expr<expression error>' may be used uninitialized in this function [-Wmaybe-uninitialized]
  104 |         jmp[0][i]=segtree.query(heights[i][0],heights[i][1]+1);
      |                                               ~~~~~~~~~~~~^
Main.cpp:104:32: warning: ''target_mem_ref' not supported by dump_expr<expression error>' may be used uninitialized in this function [-Wmaybe-uninitialized]
  104 |         jmp[0][i]=segtree.query(heights[i][0],heights[i][1]+1);
      |                   ~~~~~~~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 0 / 10
• Subtask 2: 0 / 10
• Subtask 3: 0 / 20
• Subtask 4: 0 / 20
• Subtask 5: 0 / 50