제출 #674857

#제출 시각아이디문제언어결과실행 시간메모리
674857Valera_GrinenkoToll (BOI17_toll)C++17
100 / 100
89 ms14076 KiB
// #pragma GCC optimize("Ofast,unroll-loops") // #pragma GCC target("avx,avx2,fma") #include <bits/stdc++.h> #define fi first #define se second #define pb push_back #define ppb pop_back #define mp make_pair #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() #define make_unique(x) sort(all((x))); (x).resize(unique(all((x))) - (x).begin()) typedef long long ll; typedef long double ld; using namespace std; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); template<class T> bool umin(T &a, T b) { return a > b ? (a = b, true) : false; } template<class T> bool umax(T &a, T b) { return a < b ? (a = b, true) : false; } const int N = 50001; int k, n, m, o; vector<pair<pair<int, int>, int> > qq; vector<pair<pair<int, int>, int> > g[N]; int ans[N]; ll dist[N][5][5]; void kek(int l, int r, vector<pair<pair<int, int>, int> >& curq) { vector<pair<pair<int, int>, int> > tol, tor, mid; int m = (l + r) / 2; for(int i = l; i <= r; i++) for(int a = 0; a < k; a++) for(int b = 0; b < k; b++) dist[i][a][b] = 1e18; for(int i = 0; i < k; i++) for(int j = 0; j < k; j++) dist[m][i][j] = (i == j ? 0 : 1e18); for(int i = m; i + 1 <= r; i++) { for(auto& edge : g[i]) for(int st = 0; st < k; st++) umin(dist[i + 1][st][edge.fi.se], dist[i][st][edge.fi.fi] + edge.se); } for(int i = m; i - 1 >= l; i--) { for(auto& edge : g[i - 1]) for(int fs = 0; fs < k; fs++) umin(dist[i - 1][fs][edge.fi.fi], dist[i][fs][edge.fi.se] + edge.se); } for(auto& x : curq) if(x.fi.se / k < m) tol.pb(x); else if(x.fi.fi / k > m) tor.pb(x); else { ll res = 1e18; for(int inter = 0; inter < k; inter++) umin(res, dist[x.fi.fi / k][inter][x.fi.fi % k] + dist[x.fi.se / k][inter][x.fi.se % k]); ans[x.se] = (res == 1e18 ? -1 : res); } if(l == r) return; if(!tol.empty()) kek(l, m - 1, tol); if(!tor.empty()) kek(m + 1, r, tor); } void solve() { cin >> k >> n >> m >> o; for(int i = 0; i < m; i++) { int a, b, t; cin >> a >> b >> t; g[a / k].pb(mp(mp(a % k, b % k), t)); } for(int i = 0; i < o; i++) { ans[i] = -1; int a, b; cin >> a >> b; qq.pb(mp(mp(a, b), i)); } kek(0, N / k, qq); for(int i = 0; i < o; i++) cout << ans[i] << '\n'; } int main() { ios::sync_with_stdio(0); cin.tie(0); int t = 1; // cin >> t; while(t--) solve(); return 0; } /* */
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...