Submission #673870

#	Time	Username	Problem	Language	Result	Execution time	Memory
673870		stanislavpolyn	Event Hopping (BOI22_events)	C++17	10 / 100	1584 ms	3220 KiB

events

#include <bits/stdc++.h>

#define fr(i, a, b) for (int i = (a); i <= (b); ++i)
#define rf(i, a, b) for (int i = (a); i >= (b); --i)
#define fe(x, y) for (auto& x : y)

#define fi first
#define se second
#define pb push_back
#define mp make_pair
#define mt make_tuple

#define all(x) (x).begin(), (x).end()
#define sz(x) (int)(x).size()
#define pw(x) (1LL << (x))

using namespace std;

mt19937_64 rng(228);

#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
template <typename T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#define fbo find_by_order
#define ook order_of_key

template <typename T>
bool umn(T& a, T b) {
    return a > b ? a = b, 1 : 0;
}
template <typename T>
bool umx(T& a, T b) {
    return a < b ? a = b, 1 : 0;
}

using ll = long long;
using ld = long double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
template <typename T>
using ve = vector<T>;

const int N = 1e5 + 5;

int n, q;
pii a[N];

int main() {
#ifdef LOCAL
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
#else
    ios::sync_with_stdio(0);
    cin.tie(0);
#endif

    cin >> n >> q;

    fr (i, 1, n) {
        cin >> a[i].fi >> a[i].se;
    }

    fr (i, 1, q) {
        int s, e;
        cin >> s >> e;

        if (s == e) {
            cout << "0\n";
            continue;
        }

        if (a[s].se > a[e].se) {
            cout << "impossible\n";
            continue;
        }



        int v = s;
        int ans = 0;
        bool bad = 0;
        while (1) {
            if (a[v].se >= a[e].fi) {
                ans++;
                break;
            }

            int mx = -1e9;
            int mxI = -1;
            fr (i, 1, n) {
                if (a[i].fi <= a[v].se && a[i].se >= a[v].se) {
                    if (a[i].se <= a[e].se) {
                        if (umx(mx, a[i].se)) {
                            mxI = i;
                        }
                    }
                }
            }

            if (mx == a[v].se) {
                bad = 1;
                break;
            }
            v = mxI;
            ans++;
        }
        if (!bad) {
            cout << ans << "\n";
        } else {
            cout << "impossible\n";
        }
    }

    return 0;
}

• Subtask 1: 0 / 10
• Subtask 2: 10 / 10
• Subtask 3: 0 / 15
• Subtask 4: 0 / 15
• Subtask 5: 0 / 20
• Subtask 6: 0 / 30