Submission #672371

#TimeUsernameProblemLanguageResultExecution timeMemory
672371Eae02Aliens (IOI16_aliens)C++17
60 / 100
2082 ms360644 KiB
#include "aliens.h" #include <bits/stdc++.h> using namespace std; using ll = long long; #define all(x) begin(x),end(x) struct Line { mutable ll k, m, p; bool operator<(const Line& o) const { return k < o.k; } bool operator<(ll x) const { return p < x; } }; struct LineContainer : multiset<Line, less<>> { const ll inf = LLONG_MAX; ll div(ll a, ll b) { // floored division return a / b - ((a ^ b) < 0 && a % b); } bool isect(iterator x, iterator y) { if (y == end()) { x->p = inf; return false; } if (x->k == y->k) x->p = x->m > y->m ? inf : -inf; else x->p = div(y->m - x->m, x->k - y->k); return x->p >= y->p; } void add(ll k, ll m) { auto z = insert({k, m, 0}), y = z++, x = y; while (isect(y, z)) z = erase(z); if (x != begin() && isect(--x, y)) isect(x, y = erase(y)); while ((y = x) != begin() && (--x)->p >= y->p) isect(x, erase(y)); } ll query(ll x) { assert(!empty()); auto l = *lower_bound(x); return l.k * x + l.m; } }; ll take_photos(int n, int m, int K, vector<int> r, vector<int> c) { vector<pair<ll, ll>> intvs; for (int i = 0; i < n; i++) { intvs.emplace_back(min(r[i], c[i]), -max(r[i], c[i])); } sort(all(intvs)); vector<pair<ll, ll>> st; for (auto [l, r] : intvs) { if (st.empty() || -r > st.back().second) st.emplace_back(l, -r); } //for (auto [l, r] : st) { // cerr << "intv " << l << " " << r << "\n"; //} constexpr ll inf = LLONG_MAX; auto square = [&] (ll x) { return x * x; }; vector<vector<ll>> dp(st.size() + 1, vector<ll>(K + 1)); dp[st.size()][0] = 0; for (ll i = (ll)st.size() - 1; i >= 0; i--) dp[i][0] = inf; for (ll remk = 1; remk <= K; remk++) { dp[st.size()][remk] = 0; LineContainer lc; auto addToLC = [&] (ll ie) { if (ie == 0) return; if (dp[ie][remk - 1] == inf) return; ll ex = st[ie-1].second + 1; ll bx = st[ie].first; ll k = -2 * ex; ll m = dp[ie][remk - 1] + square(ex) - square(max(ex - bx, 0LL)); lc.add(-k, -m); }; for (ll i = (ll)st.size() - 1; i >= 0; i--) { ll ans = dp[st.size()][remk - 1] + square(st.back().second - st[i].first + 1); /*for (ll ie = i + 1; ie < (ll)st.size(); ie++) { ll ex = st[ie-1].second + 1; ll bx = st[ie].first; ans = min(ans, dp[ie][remk - 1] + square(ex) - 2 * ex * st[i].first + square(st[i].first) - square(max(ex - bx, 0LL)) ); }*/ if (!lc.empty()) ans = min(ans, -lc.query(st[i].first) + square(st[i].first)); dp[i][remk] = ans; addToLC(i); } } return dp[0][K]; }
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