제출 #67048

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
67048		MrTEK	Maxcomp (info1cup18_maxcomp)	C++14	60 / 100	684 ms	20428 KiB

maxcomp

#include <bits/stdc++.h>

using namespace std;
#define mp make_pair
#define pb push_back
#define len(a) (int)a.size()
#define fi first
#define sc second
#define d1(w) cerr<<#w<<":"<<w<<endl;
#define d2(w,c) cerr<<#w<<":"<<w<<" "<<#c<<":"<<c<<endl;
#define d3(w,c,z) cerr<<#w<<":"<<w<<" "<<#c<<":"<<c<<" "<<#z<<":"<<z<<endl;
#define left ind+ind
#define right ind+ind+1
#define mid (l+r)/2
#define FAST_IO ios_base::sync_with_stdio(false);
#define endl '\n'

const int maxn = 620;
const long long LINF = 1e18;
const int LOG = 31;
const int INF = 1e9;
const int N = 1e3 + 5;
const int M = 4;
const int SQ = 350;
const int MOD = 998244353;

typedef pair <int,int> pii;

struct node {
	int val,x,y;
};

bool operator < (node a ,node b) {
	return a.val < b.val;
}

priority_queue <node> Q;

int n,m,mat[N][N],vis[N][N],ans = -INF,way[4][2] = {{1,0},{0,1},{0,-1},{-1,0}};

int main() {
	scanf("%d %d",&n,&m);
	for (int i = 1 ; i <= n ; i++)
		for (int j = 1 ; j <= m ; j++) {
			scanf("%d",&mat[i][j]);
			vis[i][j] = -INF;
			Q.push({mat[i][j],i,j});
		}
	while(len(Q)) {
		auto temp = Q.top();
		Q.pop();
		int val = temp.val, x = temp.x,y = temp.y;
		if (vis[x][y] > val) continue;
		ans = max(ans,val - mat[x][y] - 1);
		for (int i = 0 ; i < 4 ; i++) {
			int nx = x + way[i][0] , ny = y + way[i][1];
			if (nx > 0 && nx <= n && ny > 0 && ny <= m && val - 1 > vis[nx][ny]) {
				vis[nx][ny] = val - 1;
				Q.push({val - 1,nx,ny});				
			}
		}
	}
	printf("%d\n",ans);

}

컴파일 시 표준 에러 (stderr) 메시지

maxcomp.cpp: In function 'int main()':
maxcomp.cpp:42:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d %d",&n,&m);
  ~~~~~^~~~~~~~~~~~~~~
maxcomp.cpp:45:9: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
    scanf("%d",&mat[i][j]);
    ~~~~~^~~~~~~~~~~~~~~~~

• Subtask 1: 15 / 15
• Subtask 2: 15 / 15
• Subtask 3: 30 / 30
• Subtask 4: 0 / 40