Submission #667498

#	Time	Username	Problem	Language	Result	Execution time	Memory
667498		Alish	Pipes (CEOI15_pipes)	C++14	30 / 100	5082 ms	6948 KiB

pipes

#include <bits/stdc++.h>

using namespace std;

typedef long long int	ll;
typedef long double	ld;

#define F		first
#define S		second
#define pb		push_back
#define endl            '\n'
#define Mp		make_pair
#define all(x) x.begin(), x.end()
#define debug(x)  cerr << #x << " = " << x << endl
#define set_dec(x)	cout << fixed << setprecision(x);
#define fast_io                     ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define file_io                     freopen("in.txt" , "r+" , stdin) ; freopen("out.txt" , "w+" , stdout);


ll mod = 1e9+7;

ll power(ll a, ll b)
{
    return (!b ? 1 : (b & 1 ? a * power(a * a % mod, b / 2) % mod : power(a * a % mod, b / 2) % mod));
}
const int N= 100023;
vector<int> g[N] ;
int mn[N] , h[N] , par1[N] , par2[N] , vis[N];
int getPar1(int v){
    return (par1[v]==-1)?v: getPar1(par1[v]);
}
int getPar2(int v){
    return (par2[v]==-1)? v: getPar2(par2[v]);
}
bool Union1(int v, int u){
    v= getPar1(v); u = getPar1(u);
    if(u==v) return 0;
    par1[u]=v;
    return 1;
}
bool Union2(int v, int u){
    v= getPar2(v); u = getPar2(u);
    if(u==v) return 0;

    par2[u]=v;
    return 1;
}

void dfs(int v, int p ){
    vis[v]=1;
    mn[v]=h[v];
    int fuck = 0;
    for(int u: g[v]){
        if(u==p && !fuck ){fuck=1; continue;}
        if(!vis[u]){

            h[u]= h[v]+1;
            dfs(u,v);
            mn[v]= min (mn[v], mn[u]);

        }
        else{
            mn[v]= min(mn[v] , h[u]);
        }
    }
    if(p && mn[v]==h[v]) cout<<p<<" "<<v<<endl;
}
int n , m;
int i;
int main(){
    fast_io
    cin>>n>>m;
    for(i=1; i<=n; i++){
        par1[i]=-1;
        par2[i]=-1;

    }

    for(i=1 ;i<=m; i++){
        int u ,v; cin>>v>>u;
        if(Union1(v,u)){
            g[v].pb(u); g[u].pb(v);
        }
        else if(Union2(u,v)){
            g[v].pb(u); g[u].pb(v);
        }
    }
    for(i=1; i<=n; i++) if(!vis[i]) dfs(i,0);

}

• Subtask 1: 10 / 10
• Subtask 2: 10 / 10
• Subtask 3: 10 / 10
• Subtask 4: 0 / 10
• Subtask 5: 0 / 10
• Subtask 6: 0 / 10
• Subtask 7: 0 / 10
• Subtask 8: 0 / 10
• Subtask 9: 0 / 10
• Subtask 10: 0 / 10