Submission #66565

#	Time	Username	Problem	Language	Result	Execution time	Memory
66565		MANcity	Shortcut (IOI16_shortcut)	C++14	23 / 100	6 ms	760 KiB

shortcut

#include<iostream>
#include<cstdio>
#include<fstream>
#include<algorithm>
#include<cmath>
#include<map>
#include<queue>
#include<set>
#include<stack>
#include<string>
#include<cstring>
#include<vector>
#include "shortcut.h"
using namespace std;
#define for1(i,n) for(int i=1;i<=(int)n;i++)
#define for0(i,n) for(int i=0;i<=(int)n;i++)
#define forn(i,n) for(int i=n;i>=1;i--)
#define fo(i,x,y) for(int i=x;i<=(int)y;i++)
#define fr(i,x,y) for(int i=x;i>=(int)y;i--)
#define pb push_back
#define mp make_pair
#define LL long long
const LL Mod=1000*1000*1000+7;
int n;
LL d[10002];
LL x[10002];
LL c;
struct req
{
    LL x;
    LL y;
    LL k;
};
LL l1,l2,r1,r2;
void hat(req t)
{
    LL l3=(t.x-t.k)-t.y;
    LL l4=(t.x+t.k)-t.y;
    l1=max(l1,l3);
    l2=min(l2,l4);
    LL r3=(t.y-t.k)+t.x;
    LL r4=(t.y+t.k)+t.x;
    r1=max(r3,r1);
    r2=min(r4,r2);
    return;
}
int stug(LL k)
{
    l1=-100000000000;
    l2=-l1;
    r1=-100000000000;
    r2=-r1;
    vector<req> V;
    for1(i,n)
    {
        fo(j,i+1,n)
        {
            if(l1>l2 || r1>r2)
                return 0;
            if(abs(x[i]-x[j])+d[i]+d[j]>k)
            {
                if((k-d[i]-d[j]-c)<0)
                    return 0;
                req t;
                t.x=x[i];
                t.y=x[j];
                t.k=k-d[i]-d[j]-c;
                hat(t);
            }
        }
    }
    for1(i,n)
        fo(j,i+1,n)
            if((x[i]-x[j])>=l1 && (x[i]-x[j])<=l2 && (x[i]+x[j])>=r1 && (x[i]+x[j])<=r2)
                return 1;
    return 0;
}
long long find_shortcut(int n_0, vector<int> l, vector<int> d_0, int c_0)
{
    c=c_0;
    n=n_0;
    LL ma=0;
    for1(i,n)
    {
        d[i]=d_0[i-1];
        ma=max(ma,d[i]);
    }
    x[1]=0;
    for0(i,l.size()-1)
        x[i+2]=x[i+1]+l[i];
    LL r=x[n]+2*ma;
    LL l1=1;
    while(1)
    {
        if(r==(l1+1))
        {
            if(stug(l1)==1)
                return l1;
            return r;
        }
        if(l1==r)
            return l1;
        LL m=(l1+r)/2;
        if(stug(m)==1)
            r=m;
        else
            l1=(m+1);
    }
    return 0;
}

• Subtask 1: 9 / 9
• Subtask 2: 14 / 14
• Subtask 3: 0 / 8
• Subtask 4: 0 / 7
• Subtask 5: 0 / 33
• Subtask 6: 0 / 22
• Subtask 7: 0 / 4
• Subtask 8: 0 / 3