Submission #659214

#	Time	Username	Problem	Language	Result	Execution time	Memory
659214		zaneyu	Meetings 2 (JOI21_meetings2)	C++14	0 / 100	3 ms	5044 KiB

meetings2

/*input
7
1 2
2 3
3 4
4 5
2 6
3 7
*/
#include<bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
//#pragma GCC optimize("O3,unroll-loops")
//#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
using namespace __gnu_pbds;
typedef tree<long long,null_type,less_equal<long long>,rb_tree_tag,tree_order_statistics_node_update> indexed_set;
//order_of_key #of elements less than x
// find_by_order kth element
using ll=long long;
using ld=long double;
using pii=pair<ll,ll>;
#define f first
#define s second
#define pb push_back
#define REP(i,n) for(int i=0;i<n;i++)
#define REP1(i,n) for(int i=1;i<=n;i++)
#define FILL(n,x) memset(n,x,sizeof(n))
#define ALL(_a) _a.begin(),_a.end()
#define sz(x) (int)x.size()
#define SORT_UNIQUE(c) (sort(c.begin(),c.end()),c.resize(distance(c.begin(),unique(c.begin(),c.end()))))
#define GET(v,x) lower_bound(ALL(v),x)-v.begin()
const int maxn=2e5+5;
const ll INF=0x3f3f3f3f;
const ld PI=acos(-1.0l);
const ld eps=1e-6;
const ll INF64=4e18+1;
const int MOD=1e9+7;
#define lowb(x) x&(-x)
#define MNTO(x,y) x=min(x,(__typeof__(x))y)
#define MXTO(x,y) x=max(x,(__typeof__(x))y)
template<typename T1,typename T2>
ostream& operator<<(ostream& out,pair<T1,T2> P){
    out<<P.f<<' '<<P.s;
    return out;
}
template<typename T>
ostream& operator<<(ostream& out,vector<T> V){
    REP(i,sz(V)) out<<V[i]<<((i!=sz(V)-1)?"\n":"");
    return out;
}
inline ll mult(ll a,ll b){
    return a*b%MOD;
}
ll mypow(ll a,ll b){
    if(b<=0) return 1;
    ll res=1LL;
    while(b){
        if(b&1) res=mult(res,a);
        a=mult(a,a);
        b>>=1;
    }
    return res;
}
vector<int> v[maxn];
int d[maxn],pos[maxn];
void dfs(int u,int p){
    for(int x:v[u]){
        if(x==p) continue;
        d[x]=d[u]+1;
        dfs(x,u);
    }
}
int t,c;
vector<int> pth;
bool on[maxn];
bool get(int u,int p){
    if(u==t){
        return true;
    }
    for(int x:v[u]){
        if(x==p) continue;
        if(get(x,u)){
            pth.pb(x);
            return 1;
        }
    }
    return 0;
}
void mrk(int u,int p){
    pos[u]=c;
    for(int x:v[u]){
        if(on[x] or x==p) continue;
        mrk(x,u);
    }
}
int main(){
    ios::sync_with_stdio(false),cin.tie(0);
    int n;
    cin>>n;
    REP(i,n-1){
        int a,b;
        cin>>a>>b;
        --a,--b;
        v[a].pb(b),v[b].pb(a);
    }
    dfs(0,-1);
    int p=max_element(d,d+n)-d;
    d[p]=0;
    dfs(p,-1);
    int pp=max_element(d,d+n)-d;
    t=pp;
    get(p,-1);
    pth.pb(p);
    for(int x:pth) on[x]=1;
    REP(i,sz(pth)){
        c=i;
        mrk(pth[i],-1);
    }
    vector<int> v;
    REP(i,n){
        v.pb(pos[i]);
    }
    sort(ALL(v));
    REP1(i,n){
        if(i%2) cout<<1<<'\n';
        else cout<<v[sz(v)-i/2]-v[i/2-1]+1<<'\n'; 
    }
}   

• Subtask 1: 0 / 4
• Subtask 2: 0 / 16
• Subtask 3: 0 / 80