#include <bits/stdc++.h>
#include "libmean.h"
using namespace std;
#define pii pair<int, int>
int n;
int ask(int *a) {
return Meandian(a[0], a[1], a[2], a[3]);
}
bool bad(int c, int *a) {
int i=-1, j=-1, x=-1, y=-1;
for (int p=0; p<3; ++p) {
if (a[p] == c) continue;
if (i == -1) i=a[p];
else j=a[p];
}
for (int p=1; p<=n; ++p) {
if (p == i || p == c || p == j) continue;
if (x == -1) x=p;
else y=p;
}
int b[4]={i, j, x, y};
int tmp=ask(b), iv, jv;
b[0]=c; jv=ask(b);
b[1]=i; iv=ask(b);
if (tmp == iv || tmp == jv) return false;
return true;
}
pair<int, int> findEx(bool mv) {
int a[4] = {1, 2, 3, 4}, mn=ask(a);
for (int i=5; i<=n; ++i) {
int rm=-1;
for (int j=0; j<4; ++j) {
int tmp=a[j]; a[j]=i;
int x=ask(a);
a[j]=tmp;
if (mv && x < mn) rm=j, mn=x;
else if (!mv && x > mn) rm=j, mn=x;
}
if (rm != -1) a[rm]=i;
} mn=ask(a);
int x=-1;
for (int i=1; i<=n; ++i) {
bool ok=true;
for (int j=0; j<4; ++j) {
if (i == a[j]) {
ok=false;
break;
}
}
if (!ok) continue;
x=i;
}
// remove most external element
for (int i=0; i<4; ++i) {
int tmp[4]={};
for (int j=0; j<4; ++j) {
if (i == j) continue;
tmp[j]=a[j];
} tmp[i]=x;
if (mn == ask(tmp)) {
a[i]=-1;
break;
}
}
vector<int> v;
for (int i=0; i<4; ++i) {
if (a[i] == -1) continue;
v.push_back(a[i]);
} assert((int)v.size() == 3);
int b[3];
for (int i=0; i<3; ++i) b[i]=v[i];
for (int i=0; i<3; ++i) {
if (bad(b[i], b)) {
if (i == 0) return {b[1], b[2]};
else if (i == 1) return {b[0], b[2]};
return {b[0], b[1]};
}
} assert(false);
return {-1, -1};
}
int main() {
ios_base::sync_with_stdio(0);
cin.tie(NULL);
cout.tie(NULL);
n=Init();
pii mn=findEx(true);
pii mx=findEx(false);
int ans[n]={}, idx=-1, val=-1;
for (int i=1; i<=n; ++i) {
if (i == mn.first || i == mn.second) continue;
if (i == mx.first || i == mx.second) continue;
idx=i;
break;
}
int a[4]={mn.first, mn.second, idx, mx.first};
int lf=ask(a)*2, rf, wth;
a[0]=mx.second; rf=ask(a)*2;
a[2]=mn.first; wth=ask(a)*2;
val=(lf+rf-wth)/2; assert((lf+rf-wth)%2 == 0);
ans[idx-1]=val;
assert(idx != -1);
for (int i=1; i<=n; ++i) {
if (i == mn.first || i == mn.second || i == mx.first || i == mx.second) {
ans[i-1]=-1;
continue;
}
if (i == idx) continue;
int a[4]={mn.first, idx, i, mx.first};
int p=ask(a)*2; ans[i-1]=p-val;
}
Solution(ans);
}
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Correct |
1 ms |
208 KB |
Output is correct |
2 |
Correct |
1 ms |
208 KB |
Output is correct |
3 |
Correct |
1 ms |
208 KB |
Output is correct |
4 |
Correct |
2 ms |
208 KB |
Output is correct |
5 |
Correct |
2 ms |
208 KB |
Output is correct |
6 |
Correct |
3 ms |
208 KB |
Output is correct |
7 |
Correct |
4 ms |
208 KB |
Output is correct |
8 |
Correct |
6 ms |
208 KB |
Output is correct |
9 |
Correct |
9 ms |
208 KB |
Output is correct |
10 |
Correct |
9 ms |
208 KB |
Output is correct |