Submission #657517

#TimeUsernameProblemLanguageResultExecution timeMemory
657517senthetaCatfish Farm (IOI22_fish)C++17
23 / 100
1084 ms74052 KiB
#include "fish.h" // author : sentheta aka vanwij #include<iostream> #include<iomanip> #include<algorithm> #include<cassert> #include<random> #include<chrono> #include<cmath> #include<string> #include<vector> #include<bitset> #include<queue> #include<stack> #include<map> #include<set> using namespace std; #define Int long long #define V vector #define pii pair<int,int> #define ff first #define ss second #define rand() (uniform_int_distribution<int>(0,1<<30)(rng)) mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()); #define pow2(x) (1LL<<(x)) #define msb(x) (63-__builtin_clzll(x)) #define bitcnt(x) (__builtin_popcountll(x)) #define nl '\n' #define _ << ' ' << #define all(x) (x).begin(), (x).end() #define rep(i,a,b) for(int i = (int)(a); i < (int)(b); i++) #define dbg(x) if(1) cout << "?" << #x << " : " << (x) << endl << flush; const Int N = 2e5+5; Int n, m; V<Int> x, y, w; V<pii> g[N]; Int dp[N][8][8]; Int max_weights(int _n,int _m,V<int> _x,V<int> _y,V<int> _w){ n = _n; m = _m; x = V<Int>(all(_x)); y = V<Int>(all(_y)); w = V<Int>(all(_w)); rep(i,0,m){ g[x[i]].push_back({y[i], w[i]}); // dbg(x[i]); // c[x[i]] = w[i]; } rep(i,0,n){ sort(all(g[i])); g[i].push_back({n, 0}); // dbg(i); // for(auto[j,k] : g[i]) cout << j _ k << nl; } // cout << nl; rep(i,1,n){ // dbg(i); rep(p,0,i==1 ? 1:g[i-2].size()) rep(q,0,g[i-1].size()) rep(r,0,g[i].size()){ Int cost = dp[i-1][p][q]; int pp = i==1 ? 0:g[i-2][p].ff; int qq = g[i-1][q].ff; int rr = g[i][r].ff; // dbg(pp); dbg(qq); dbg(rr); rep(j,q,g[i-1].size()) if(pp-1<g[i-1][j].ff && g[i-1][j].ff<=rr-1){ cost += g[i-1][j].ss; } rep(j,r,g[i].size()) if(g[i][j].ff <= qq-1){ cost += g[i][j].ss; } // dbg(cost); // cout << nl; dp[i][q][r] = max(dp[i][q][r], cost); } } // dbg(dp[1][0][0]); // dbg(dp[1][0][1]); // dbg(dp[1][1][0]); // dbg(dp[1][1][1]); Int ans = 0; rep(p,0,g[n-2].size()) rep(q,0,g[n-1].size()){ ans = max(ans, dp[n-1][p][q]); } return ans; return 0; }
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