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답안 #651761

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
651761 2022-10-20T01:40:33 Z ghostwriter 열대 식물원 (Tropical Garden) (IOI11_garden) C++14
69 / 100
 5000 ms 16820 KB 
#pragma GCC optimize ("Ofast")
#pragma GCC target ("avx2")
#include "garden.h"
#include "gardenlib.h"
#include <bits/stdc++.h>
using namespace std;
#ifdef LOCAL
#include <debug.h>
#include "grader.cpp"
#else
#define debug(...)
#endif
#define ft front
#define bk back
#define st first
#define nd second
#define ins insert
#define ers erase
#define pb push_back
#define pf push_front
#define _pb pop_back
#define _pf pop_front
#define lb lower_bound
#define ub upper_bound
#define mtp make_tuple
#define bg begin
#define ed end
#define all(x) x.bg(), x.ed()
#define sz(x) (int)x.size()
typedef long long ll; typedef unsigned long long ull;
typedef double db; typedef long double ldb;
typedef pair<int, int> pi; typedef pair<ll, ll> pll;
typedef vector<int> vi; typedef vector<ll> vll; typedef vector<pi> vpi; typedef vector<pll> vpll;
typedef string str;
template<typename T> T gcd(T a, T b) { return (b == 0? a : gcd(b, a % b)); }
template<typename T> T lcm(T a, T b) { return a / gcd(a, b) * b; }
#define FOR(i, l, r) for (int i = l; i <= r; ++i)
#define FOS(i, r, l) for (int i = r; i >= l; --i)
#define FRN(i, n) for (int i = 0; i < n; ++i)
#define FSN(i, n) for (int i = n - 1; i >= 0; --i)
#define EACH(i, x) for (auto &i : x)
#define WHILE while
#define file "TEST"
mt19937 rd(chrono::steady_clock::now().time_since_epoch().count());
ll rand(ll l, ll r) { return uniform_int_distribution<ll>(l, r)(rd); }
/*
----------------------------------------------------------------
    END OF TEMPLATE
----------------------------------------------------------------
    Tran The Bao - ghostwriter
    Training for VOI23 gold medal
----------------------------------------------------------------
    GOAT
----------------------------------------------------------------
*/
const int MAXN = 15e4;
int ind[MAXN][2], c[MAXN][2], c1[MAXN][2], s[MAXN][2], d[MAXN][2];
vi adj[MAXN];
vpi e;
pi nxt(pi x) {
    int u = x.st;
    bool stt = x.nd;
    int id = (!stt? 0 : sz(adj[u]) == 1? 0 : 1);
    int nxtv = e[adj[u][id]].st == u? e[adj[u][id]].nd : e[adj[u][id]].st;
    return {nxtv, adj[u][id] == adj[nxtv][0]? 1 : 0};
}
int cal(int &N, int &P, int &x) {
    memset(c, 0, sizeof c);
    int ans = 0;
    FRN(i, N)
    FRN(j, 2) {
        if (ind[i][j]) continue;
        int x1 = x;
        if (x1 > d[i][j]) {
            x1 -= d[i][j];
            x1 %= s[i][j];
            x1 += d[i][j];
        }
        pi cur = {i, j};
        FOR(z, 1, x1) cur = nxt(cur);
        if (!j && cur.st == P) ++ans;
        c[i][j] = 1;
        pi cur1 = nxt({i, j});
        WHILE(!c[cur1.st][cur1.nd]) {
            cur = nxt(cur);
            if (!cur1.nd && cur.st == P) ++ans;
            c[cur1.st][cur1.nd] = 1;
            cur1 = nxt(cur1);
        }
    }
    FRN(i, N)
    FRN(j, 2) {
        if (c[i][j]) continue;
        int x1 = x % s[i][j];
        pi cur = {i, j};
        FOR(z, 1, x1) cur = nxt(cur);
        if (!j && cur.st == P) ++ans;
        c[i][j] = 1;
        pi cur1 = nxt({i, j});
        WHILE(!c[cur1.st][cur1.nd]) {
            cur = nxt(cur);
            if (!cur1.nd && cur.st == P) ++ans;
            c[cur1.st][cur1.nd] = 1;
            cur1 = nxt(cur1);
        }   
    }
    return ans;
}
void count_routes(int N, int M, int P, int R[][2], int Q, int G[]) {
    FRN(i, M) {
        int u = R[i][0], v = R[i][1];
        e.pb({u, v});
        if (sz(adj[u]) < 2) adj[u].pb(i);
        if (sz(adj[v]) < 2) adj[v].pb(i);
    }
    FRN(i, N)
    FRN(j, 2) {
        pi tmp1 = nxt({i, j});
        ind[tmp1.st][tmp1.nd] = 1;
        if (c1[i][j]) continue;
        vpi ver;
        pi cur = {i, j};
        WHILE(1) {
            if (!c[cur.st][cur.nd]) ver.pb(cur);
            ++c[cur.st][cur.nd];
            cur = nxt(cur);
            if (c1[cur.st][cur.nd] || c[cur.st][cur.nd] == 2) break;
        }
        reverse(all(ver));
        if (c[ver.ft().st][ver.ft().nd] == 2) {
            int cnt = 0, h = 0;
            EACH(z, ver) if (c[z.st][z.nd] == 2) ++cnt;
            EACH(z, ver) {
                if (c[z.st][z.nd] == 1) ++h;
                s[z.st][z.nd] = cnt;
                d[z.st][z.nd] = h;
            }
        }
        else {
            pi tmp = nxt(ver.ft());
            int cnt = s[tmp.st][tmp.nd], h = d[tmp.st][tmp.nd];
            EACH(z, ver) {
                ++h;
                s[z.st][z.nd] = cnt;
                d[z.st][z.nd] = h;
            }
        }
        EACH(z, ver) c1[z.st][z.nd] = 1;
    }
    FRN(q, Q) answer(cal(N, P, G[q]));
}
/*
5 5 2
1 0
1 2
3 2
1 3
4 2
2
3 1
1 2

0 0 1 1
0 1 1 1
1 0 0 1
1 1 2 1
2 0 1 0
2 1 3 1
3 0 2 0
3 1 1 0
4 0 2 0
4 1 2 0
----------------------------------------------------------------
From Benq:
    stuff you should look for
        * int overflow, array bounds
        * special cases (n=1?)
        * do smth instead of nothing and stay organized
        * WRITE STUFF DOWN
        * DON'T GET STUCK ON ONE APPROACH
----------------------------------------------------------------
*/

Subtask #1
49.0 / 49.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 5076 KB Output is correct
2 Correct 4 ms 5092 KB Output is correct
3 Correct 4 ms 5076 KB Output is correct
4 Correct 3 ms 4936 KB Output is correct
5 Correct 3 ms 4948 KB Output is correct
6 Correct 3 ms 5076 KB Output is correct
7 Correct 3 ms 4948 KB Output is correct
8 Correct 3 ms 5076 KB Output is correct
9 Correct 6 ms 5204 KB Output is correct

Subtask #2
20.0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 5076 KB Output is correct
2 Correct 4 ms 5092 KB Output is correct
3 Correct 4 ms 5076 KB Output is correct
4 Correct 3 ms 4936 KB Output is correct
5 Correct 3 ms 4948 KB Output is correct
6 Correct 3 ms 5076 KB Output is correct
7 Correct 3 ms 4948 KB Output is correct
8 Correct 3 ms 5076 KB Output is correct
9 Correct 6 ms 5204 KB Output is correct
10 Correct 3 ms 4948 KB Output is correct
11 Correct 285 ms 6924 KB Output is correct
12 Correct 373 ms 8216 KB Output is correct
13 Correct 42 ms 11964 KB Output is correct
14 Correct 197 ms 15612 KB Output is correct
15 Correct 202 ms 15832 KB Output is correct
16 Correct 1616 ms 12916 KB Output is correct
17 Correct 132 ms 11892 KB Output is correct
18 Correct 115 ms 8148 KB Output is correct
19 Correct 223 ms 15588 KB Output is correct
20 Correct 243 ms 15900 KB Output is correct
21 Correct 702 ms 12848 KB Output is correct
22 Correct 169 ms 11916 KB Output is correct
23 Correct 657 ms 16820 KB Output is correct

Subtask #3
0 / 31.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 5076 KB Output is correct
2 Correct 4 ms 5092 KB Output is correct
3 Correct 4 ms 5076 KB Output is correct
4 Correct 3 ms 4936 KB Output is correct
5 Correct 3 ms 4948 KB Output is correct
6 Correct 3 ms 5076 KB Output is correct
7 Correct 3 ms 4948 KB Output is correct
8 Correct 3 ms 5076 KB Output is correct
9 Correct 6 ms 5204 KB Output is correct
10 Correct 3 ms 4948 KB Output is correct
11 Correct 285 ms 6924 KB Output is correct
12 Correct 373 ms 8216 KB Output is correct
13 Correct 42 ms 11964 KB Output is correct
14 Correct 197 ms 15612 KB Output is correct
15 Correct 202 ms 15832 KB Output is correct
16 Correct 1616 ms 12916 KB Output is correct
17 Correct 132 ms 11892 KB Output is correct
18 Correct 115 ms 8148 KB Output is correct
19 Correct 223 ms 15588 KB Output is correct
20 Correct 243 ms 15900 KB Output is correct
21 Correct 702 ms 12848 KB Output is correct
22 Correct 169 ms 11916 KB Output is correct
23 Correct 657 ms 16820 KB Output is correct
24 Correct 71 ms 5060 KB Output is correct
25 Execution timed out 5068 ms 6864 KB Time limit exceeded
26 Halted 0 ms 0 KB -