| # | Time | Username | Problem | Language | Result | Execution time | Memory | 
|---|---|---|---|---|---|---|---|
| 650704 | Alexandruabcde | Road Closures (APIO21_roads) | C++14 | 2100 ms | 24100 KiB | 
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "roads.h"
#include <vector>
#include <bits/stdc++.h>
using namespace std;
constexpr int NMAX = 100005;
typedef long long LL;
constexpr LL INF = 1LL * 1e15;
struct muchie {
    int x, y;
    LL cost;
};
muchie E[NMAX];
vector <int> G[NMAX];
LL dp[NMAX][2];
void Dfs (int k, int Node, int dad = -1) {
    for (auto it : G[Node]) {
        int to = (E[it].x == Node ? E[it].y : E[it].x);
        if (to == dad) continue;
        Dfs(k, to, Node);
    }
    int grad = 0;
    vector <LL> V;
    LL sum = 0;
    for (auto it : G[Node]) {
        int to = (E[it].x == Node ? E[it].y : E[it].x);
        if (to == dad) continue;
        ++ grad;
        V.push_back(dp[to][1] - dp[to][0]);
        sum += dp[to][0];
    }
    dp[Node][0] = INF;
    dp[Node][1] = INF;
    sort(V.begin(), V.end());
    if (k > 0) {
        dp[Node][0] = sum;
        for (int i = 0; i < max(0, grad - k + 1); ++ i )
            dp[Node][0] += V[i];
        for (int i = max(0, grad - k + 1); i < V.size() && V[i] < 0; ++ i )
            dp[Node][0] += V[i];
    }
    if (dad == -1) {
        dp[Node][1] = sum;
        for (int i = 0; i < max(0, grad - k); ++ i )
            dp[Node][1] += V[i];
        for (int i = max(0, grad - k); i < V.size() && V[i] < 0; ++ i )
            dp[Node][1] += V[i];
    }
    for (auto it : G[Node]) {
        int to = (E[it].x == Node ? E[it].y : E[it].x);
        if (to != dad) continue;
        dp[Node][1] = sum + E[it].cost;
        for (int i = 0; i < max(0, grad - k); ++ i )
            dp[Node][1] += V[i];
        for (int i = max(0, grad - k); i < V.size() && V[i] < 0; ++ i )
            dp[Node][1] += V[i];
        break;
    }
}
std::vector<long long> minimum_closure_costs(int N, std::vector<int> U,
                                             std::vector<int> V,
                                             std::vector<int> W) {
    for (int i = 1; i < N; ++ i ) {
        E[i] = {U[i-1], V[i-1], 1LL * W[i-1]};
        G[U[i-1]].push_back(i);
        G[V[i-1]].push_back(i);
    }
    vector <LL> ans;
    for (int k = 0; k < N; ++ k ) {
        Dfs(k, 0);
        ans.push_back(dp[0][1]);
    }
    return ans;
}
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