Submission #650341

#TimeUsernameProblemLanguageResultExecution timeMemory
650341600MihneaFire (JOI20_ho_t5)C++17
1 / 100
1085 ms23732 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; struct Op { int limit; int k; int id; }; bool operator < (Op a, Op b) { return a.k < b.k; } vector<pair<ll, int>> treemxa; vector<ll> a; void buildtreemxa(int v, int tl, int tr) { if (tl == tr) { treemxa[v] = {a[tl], tl}; } else { int tm = (tl + tr) / 2; buildtreemxa(2 * v, tl, tm); buildtreemxa(2 * v + 1, tm + 1, tr); treemxa[v] = max(treemxa[2 * v], treemxa[2 * v + 1]); } } pair<ll, int> getmxa(int v, int tl, int tr, int l, int r) { if (tr < l || r < tl) { return {-1LL, 0}; } if (l <= tl && tr <= r) { return treemxa[v]; } int tm = (tl + tr) / 2; return max(getmxa(2 * v, tl, tm, l, r), getmxa(2 * v + 1, tm + 1, tr, l, r)); } int main() { #ifndef ONPC ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); #endif int n, q; cin >> n >> q; a.resize(n); for (int i = 0; i < n; i++) { cin >> a[i]; } treemxa.resize(4 * (n + 7)); buildtreemxa(1, 0, n - 1); // l, r, t vector<ll> prn(2 * q, 0); vector<Op> ops; for (int i = 0; i < q; i++) { int l, r, t; cin >> t >> l >> r; l--, r--; ops.push_back({l - 1, t, i}); ops.push_back({r, t, i + q}); } // next bigger vector<int> s(n, (int) 1e9 + 7), f(n, -((int) 1e9 + 7)); { vector<int> stk; for (int i = n - 1; i >= 0; i--) { while (!stk.empty() && a[stk.back()] < a[i]) { stk.pop_back(); } if (!stk.empty()) { s[i] = stk.back() - 1; } stk.push_back(i); } } { vector<int> stk; for (int i = 0; i < n; i++) { while (!stk.empty() && a[stk.back()] <= a[i]) { stk.pop_back(); } if (!stk.empty()) { f[i] = stk.back() + 1; } stk.push_back(i); } } sort(ops.begin(), ops.end()); ll h = 0; for (auto &it : ops) { int limit = it.limit; if (limit < 0) { //cout << "skip\n"; continue; } int k = it.k; int id = it.id; ll sol = 0; { int i = getmxa(1, 0, n - 1, max(0, limit - k), limit).second; sol += 1LL * a[i] * (limit - min(s[i], i + k)); } for (int i = 0; i <= limit; i++) { int q = max(i, f[i] + k); int w = min(s[i], i + k); if (f[i] <= min(limit, s[i]) - k) { sol += 1LL * a[i] * (w - q + 1); } } prn[id] = sol; } for (int i = 0; i < q; i++) { h = h * 777777 + prn[i]; h = h * 777777 + prn[i + q]; cout << prn[i + q] - prn[i] << "\n"; } #ifdef ONPC assert(h == 5799234416310137250); cout << "h = " << h << "\n"; #endif return 0; }
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