Submission #647991

#	Time	Username	Problem	Language	Result	Execution time	Memory
647991		mihneacazan	Sum Zero (RMI20_sumzero)	C++17	61 / 100	111 ms	34864 KiB

sumzero

#include <bits/stdc++.h>
#define pb push_back
#define ppb pop_back
#define pf push_front
#define ppf pop_front
#define ll long long
#define zeros(x) ( (x ^ (x - 1)) & x )

using namespace std;
unsigned seed = chrono::system_clock::now().time_since_epoch().count();
mt19937 rng(seed);
#define rand() rng()
/*const long long mod = 998244353;
long long fct[200005],invfct[200005],inv[200005];
long long put2[200005];
long long lgput (long long a, long long exp)
{
    long long rz=1;
    while(exp)
        if(exp&1)
            exp^=1,rz=rz*1LL*a%mod;
        else
            exp>>=1,a=a*1LL*a%mod;
    return rz;
}
long long cmb (long long n, long long k)
{
    if(n<k || k<0 || n<0)
        return 0;
    return fct[n]*1LL*invfct[k]%mod*1LL*invfct[n-k]%mod;
}
void init ()
{
    inv[1]=fct[0]=fct[1]=invfct[0]=invfct[1]=put2[0]=1,put2[1]=2;
    for(long long i=2;i<=200000;++i)
        put2[i]=put2[i-1]*2LL%mod,inv[i]=(mod-mod/i)*1LL*inv[mod%i]%mod,fct[i]=i*1LL*fct[i-1]%mod,invfct[i]=inv[i]*1LL*invfct[i-1]%mod;
}
long long v[200005];*/
const int N=2e5+5;
map<ll,int> last;
int dp[N][20],v[N];
void solve()
{
    int n;
    ll sum=0;
    cin>>n;
    for(int i=1;i<=n;i++)
        cin>>v[i];
    last[0]=n+1;
    for(int j=0;j<=18;j++)
    {
        for(int i=0;i<=n+1;i++)
            dp[i][j]=-1;
    }
    for(int i=n;i>=1;i--)
    {
        sum+=v[i];
        dp[i][0]=dp[i+1][0];
        if(last[sum] && (last[sum]-1<dp[i][0] || dp[i][0]==-1))
           dp[i][0]=last[sum]-1;
        last[sum]=i;
    }
    for(int i=1;i<=18;i++)
    {
        for(int j=1;j<=n;j++)
            dp[j][i]=dp[dp[j][i-1]+1][i-1];
    }
    int q;
    cin>>q;
    while(q--)
    {
        ll l,r,ans=0;
        cin>>l>>r;
        while(l<=r)
        {
            bool ok=0;
            for(int j=18;j>=0;j--)
            {
                if(dp[l][j]<=r && dp[l][j]!=-1)
                {
                    ans+=(1<<j);
                    ok=1;
                    l=dp[l][j]+1;
                    break;
                }
            }
            if(!ok)
               break;
        }
        cout<<ans<<"\n";
    }
}
int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    int t=1;
    //cin>>t;
    while(t--)
        solve();
    return 0;
}

• Subtask 1: 22 / 22
• Subtask 2: 39 / 39
• Subtask 3: 0 / 39