# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
639912 | ghostwriter | Secret (JOI14_secret) | C++14 | 446 ms | 8264 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "secret.h"
#include <bits/stdc++.h>
using namespace std;
#ifdef LOCAL
#include <debug.h>
#include "grader.cpp"
#endif
#define st first
#define nd second
#define pb push_back
#define pf push_front
#define _pb pop_back
#define _pf pop_front
#define lb lower_bound
#define ub upper_bound
#define mtp make_tuple
#define all(x) (x).begin(), (x).end()
#define sz(x) (int)(x).size()
typedef long long ll; typedef unsigned long long ull;
typedef double db; typedef long double ldb;
typedef pair<int, int> pi; typedef pair<ll, ll> pll;
typedef vector<int> vi; typedef vector<ll> vll; typedef vector<pi> vpi; typedef vector<pll> vpll;
typedef string str;
template<typename T> T gcd(T a, T b) { return (b == 0? a : gcd(b, a % b)); }
template<typename T> T lcm(T a, T b) { return a / gcd(a, b) * b; }
#define FOR(i, l, r) for (int (i) = (l); (i) <= (r); ++(i))
#define FOS(i, r, l) for (int (i) = (r); (i) >= (l); --(i))
#define EACH(i, x) for (auto &(i) : (x))
#define WHILE while
#define file "TEST"
mt19937 rd(chrono::steady_clock::now().time_since_epoch().count());
ll rand(ll l, ll r) { return uniform_int_distribution<ll>(l, r)(rd); }
/*
Tran The Bao
CTL - Da Lat
Cay ngay cay dem nhung deo duoc cong nhan
*/
const int MAXN = 1000;
int n, d[MAXN][MAXN];
void build(int l, int r, int a[]) {
if (l == r) {
d[l][l] = a[l];
return;
}
int mid = (l + r) / 2;
FOR(i, mid + 1, r)
if (i == mid + 1) d[i][i] = a[i];
else d[mid + 1][i] = Secret(d[mid + 1][i - 1], a[i]);
FOS(i, mid, l)
if (i == mid) d[i][i] = a[i];
else d[i][mid] = Secret(a[i], d[i + 1][mid]);
build(l, mid, a);
build(mid + 1, r, a);
}
void Init(int N, int A[]) {
n = N;
build(0, N - 1, A);
}
int Query(int L, int R) {
int l = 0, r = n - 1;
WHILE(1) {
int mid = l + (r - l) / 2;
if (L <= mid && mid <= R) {
int a = d[L][mid], b = (mid + 1 > R? -1 : d[mid + 1][R]);
if (b != -1) return Secret(a, b);
return a;
}
if (mid < L) l = mid + 1;
else r = mid;
}
return 0;
}
Compilation message (stderr)
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