Submission #635290

#TimeUsernameProblemLanguageResultExecution timeMemory
635290uroskLet's Win the Election (JOI22_ho_t3)C++14
100 / 100
159 ms4428 KiB
#define here cerr<<"===========================================\n" #define dbg(x) cerr<<#x<<": "<<x<<endl; #include <bits/stdc++.h> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/assoc_container.hpp> #define ld double #define ll long long #define llinf 100000000000000000LL // 10^17 #define pb push_back #define popb pop_back #define fi first #define sc second #define endl '\n' #define pll pair<ll,ll> #define pld pair<ld,ld> #define sz(a) (ll)(a.size()) #define all(a) a.begin(),a.end() #define ceri(a,l,r) {cerr<<#a<<": ";for(ll i_ = l;i_<=r;i_++) cerr<<a[i_]<< " ";cerr<<endl;} #define daj_mi_malo_vremena ios_base::sync_with_stdio(false);cerr.tie(0);cout.tie(0);cin.tie(0); using namespace std; using namespace __gnu_pbds; /* ll add(ll x,ll y){ x+=y; if(x<0){ x%=mod; x+=mod; }else{ if(x>=mod) x%=mod; } return x; } ll mul(ll a,ll b){ ll ans = (a*b)%mod; if(ans<0) ans+=mod; return ans; } typedef tree<int,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_set; typedef tree<int,null_type,less_equal<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_multiset; mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()); ll rnd(ll l,ll r){ return uniform_int_distribution<ll>(l,r)(rng); } */ #define maxn 505 ll n,k; ll calc[maxn][maxn]; ld dp[maxn][maxn]; pll a[maxn]; bool cmp(pll a,pll b){ if(a.sc!=b.sc) return a.sc<b.sc; return a.fi>b.fi; } int main(){ daj_mi_malo_vremena cout<<fixed<<setprecision(30); cerr<<fixed<<setprecision(30); cin >> n >> k; for(ll i = 1;i<=n;i++) cin >> a[i].fi >> a[i].sc; for(ll i = 1;i<=n;i++) if(a[i].sc==-1) a[i].sc = 2000; sort(a+1,a+1+n,cmp); for(ll i = 0;i<=n+1;i++) for(ll j = 0;j<=n+1;j++) dp[i][j] = calc[i][j] = llinf; calc[n+1][0] = 0; for(ll i = n;i>=1;i--){ calc[i][0] = 0; for(ll j = 1;j<=n;j++) calc[i][j] = min(calc[i+1][j],calc[i+1][j-1]+a[i].fi); } ld ans = llinf; dp[0][0] = 0; for(ll e = 0;e<=k;e++){ for(ll i = 1;i<=n;i++){ dp[0][0] = 0; for(ll j = 0;j<=e;j++){ dp[i][j] = dp[i-1][j] + 1.0*a[i].fi/(e+1); if(a[i].sc!=2000&&j) dp[i][j] = min(dp[i][j],dp[i-1][j-1]+1.0*a[i].sc/j); } } for(ll i = e;i<=k;i++) ans = min(ans,dp[i][e]+1.0*calc[i+1][k-i]/(e+1)); } cout<<ans<<endl; return 0; }
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