Submission #634680

#TimeUsernameProblemLanguageResultExecution timeMemory
634680uroskRobot (JOI21_ho_t4)C++14
58 / 100
3080 ms108088 KiB
#define here cerr<<"===========================================\n" #define dbg(x) cerr<<#x<<": "<<x<<endl; #include <bits/stdc++.h> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/assoc_container.hpp> #define ld double #define ll long long #define llinf 100000000000000000LL // 10^17 #define pb push_back #define popb pop_back #define fi first #define sc second #define endl '\n' #define pll pair<ll,ll> #define pld pair<ld,ld> #define sz(a) (ll)(a.size()) #define all(a) a.begin(),a.end() #define ceri(a,l,r) {cerr<<#a<<": ";for(ll i_ = l;i_<=r;i_++) cerr<<a[i_]<< " ";cerr<<endl;} #define daj_mi_malo_vremena ios_base::sync_with_stdio(false);cerr.tie(0);cout.tie(0);cin.tie(0); using namespace std; using namespace __gnu_pbds; /* ll add(ll x,ll y){ x+=y; if(x<0){ x%=mod; x+=mod; }else{ if(x>=mod) x%=mod; } return x; } ll mul(ll a,ll b){ ll ans = (a*b)%mod; if(ans<0) ans+=mod; return ans; } typedef tree<int,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_set; typedef tree<int,null_type,less_equal<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_multiset; mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()); ll rnd(ll l,ll r){ return uniform_int_distribution<ll>(l,r)(rng); } */ #define maxn 100005 ll n,m; map<int,ll> sum[maxn]; map<int,ll> mx[maxn]; ll d[maxn]; bool vis[maxn],vis2[maxn]; map<int,ll> d2[maxn]; struct nxt{ ll fi,p,c,d; }; bool cmp(nxt a,nxt b){ if(a.d!=b.d) return a.d>b.d; return a.p>b.p; } map<int,vector<nxt> > g[maxn]; queue<nxt> pq; int main(){ daj_mi_malo_vremena cin >> n >> m; for(ll i = 1;i<=m;i++){ ll x,y,c,p; cin >> x >> y >> c >> p; sum[x][c]+=p; sum[y][c]+=p; mx[x][c] = max(mx[x][c],p); mx[y][c] = max(mx[y][c],p); g[x][c].pb({y,p,c,0}); g[y][c].pb({x,p,c,0}); } fill(d,d+maxn,llinf); d[1] = 0; pq.push({1,0,0,0}); while(sz(pq)){ nxt e = pq.front(); pq.pop(); ll u = e.fi; bool f = !!e.c; if(!f&&e.d!=d[u]) continue; if(f&&e.d!=d2[u][e.c]) continue; else vis2[u] = 1; if(f){ for(nxt a : g[u][e.c]){ ll s = a.fi; ll c = a.c; ll p = a.p; ll w = sum[u][c]-p; if(e.d+w<d[s]){ d[s] = e.d + w; pq.push({s,0,0,d[s]}); } } continue; } for(auto it : g[u]){ for(nxt a : it.sc){ ll s = a.fi; ll c = a.c; ll p = a.p; ll w = min(p,sum[u][c]-p); if(e.d+w<d[s]){ d[s] = e.d + w; pq.push({s,0,0,d[s]}); } if(d2[s].count(c)==0||e.d<d2[s][c]){ d2[s][c] = e.d; pq.push({s,p,c,e.d}); } } } } ll ans = d[n]; if(ans==llinf) ans = -1; cout<<ans<<endl; return 0; }
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