Submission #634300

#	Time	Username	Problem	Language	Result	Execution time	Memory
634300		inksamurai	Klavir (COCI17_klavir)	C++17	160 / 160	368 ms	33740 KiB

klavir

#include <bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=0;i<n;i++)
#define rng(i,c,n) for(int i=c;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define fi first
#define se second
#define pb push_back
#define sz(a) (int)a.size()
#define vec(...) vector<__VA_ARGS__>
#define _3PGDklf ios::sync_with_stdio(0),cin.tie(0)
typedef long long ll;
using pii=pair<int,int>;
using vi=vector<int>;
void print(){cout<<'\n';}
template<class h,class...t>
void print(const h&v,const t&...u){cout<<v<<' ',print(u...);}
// e

//snuke's mod int
template <ll mod>
struct modint{
	ll x; // typedef long long ll;
	modint(ll x=0):x((x%mod+mod)%mod){}
	modint operator-()const{return modint(-x);}
	modint& operator+=(const modint a){if((x+=a.x)>=mod) x-=mod; return *this;}
	modint& operator-=(const modint a){if((x+=mod-a.x)>=mod) x-=mod; return *this;}
	modint& operator*=(const modint a){(x*=a.x)%=mod; return *this;}
	modint operator+(const modint a)const{modint res(*this); return res+=a;}
	modint operator-(const modint a)const{modint res(*this); return res-=a;}
	modint operator*(const modint a)const{modint res(*this); return res*=a;}
	modint pow(ll n)const{
		modint res=1,x(*this);
		while(n){
			if(n&1)res*=x;
			x*=x;
			n>>=1;
		}
		return res;
	}
	modint inv()const{return pow(mod-2);}
};

using mint=modint<1000000007>;

signed main(){
_3PGDklf;
	int n,m;
	cin>>n>>m;
	vi a(m);
	rep(i,m){
		cin>>a[i];
		a[i]-=1;
	}
	vi pi(m+1);
	auto find_link=[&](int i,int ch)->int{
		if(!i){
			return ch==a[0];
		}
		int j=pi[i-1];
		while(j and a[j]!=ch){
			j=pi[j-1];
		}
		j+=a[j]==ch;
		return j;
	};
	using pmi=pair<mint,mint>;
	vec(pmi) e(m+1);
	// e(0)*p.fi+p.se
	e[0]={1,0};
	rep(i,m){
		int u=a[i];
		int link=find_link(i,u);
		pmi sun={0,0};
		if(!i){
			sun.fi=e[0].fi*mint(n-1);
			sun.se=e[0].se*mint(n-1)+mint(n-1);
		}else{
			int nj=pi[i-1];
			sun.fi=mint(n)*e[nj].fi-e[link].fi;
			sun.se=mint(n)*e[nj].se-(e[link].se+mint(1));
		}
		pmi now;
		now.fi=mint(n)*e[i].fi-sun.fi;
		now.se=mint(n)*e[i].se-sun.se-mint(1);
		e[i+1]=now;
		mint x=-now.se*now.fi.inv();
		cout<<x.x<<" ";
		if(i>0){
			pi[i]=link;
		}
	}
}

• Subtask 1: 16 / 16
• Subtask 2: 16 / 16
• Subtask 3: 16 / 16
• Subtask 4: 16 / 16
• Subtask 5: 16 / 16
• Subtask 6: 16 / 16
• Subtask 7: 16 / 16
• Subtask 8: 16 / 16
• Subtask 9: 16 / 16
• Subtask 10: 16 / 16