Submission #634108

#	Time	Username	Problem	Language	Result	Execution time	Memory
634108		SOCIOPATE	Split the sequence (APIO14_sequence)	C++17	39 / 100	2084 ms	32832 KiB

sequence

#ifdef LOCAL
    #define _GLIBCXX_DEBUG
#endif

#include <bits/stdc++.h>

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;

#define pll pair<ll, ll>
#define pii pair<int, int>
#define pdd pair<ld, ld>
#define ff first
#define ss second
#define all(v) v.begin(),v.end()

typedef tree<
    int,
    null_type,
    less<int>,
    rb_tree_tag,
    tree_order_statistics_node_update> ordset;

#pragma GCC optimize("-O3")
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("-Os")

ll INF = 2e18;
ll mod = 1e9 + 7;

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

ll binpow(ll n, ll m){
    if(m == 0) return 1ll;
    if(m & 1ll) return n * binpow(n, m / 2ll);
    ll b = binpow(n, m / 2ll);
    return b*b;
}

void solve(){
    int n, k;
    cin >> n >> k;
    vector<ll> a(n), pref(n);
    for(int i = 0; i < n; i++) {
        cin >> a[i];
        pref[i] = (i ? pref[i - 1] : 0) + a[i];
    }
    vector<vector<ll>> dp(n, vector<ll>(k + 2, 0)), pr(n, vector<ll>(k + 2, -1));
    auto sum = [&](int l, int r){
        return pref[r] - (l ? pref[l - 1] : 0);
    };
    for(int i = 0; i < n; i++) dp[i][1] = pref[i]*(pref[n - 1]-pref[i]);
    for(int i = 1; i < n; i++){
        for(int j = 2; j <= min(i + 1, k + 1); j++){
            for(int i1 = j - 2; i1 < i; i1++){
                ll newdp;
                if(i == n - 1 && j == k + 1) newdp = dp[i1][j - 1];
                else newdp = sum(i1 + 1, i)*sum(i + 1, n - 1) + dp[i1][j - 1];
                if(dp[i][j] < newdp){
                    pr[i][j] = i1;
                    dp[i][j] = newdp;
                }
            }
        }
    }
    vector<int> ans;
    int lst = n - 1;
    for(int i = k + 1; i >= 2; i--){
        lst = pr[lst][i];
        ans.push_back(lst);
    }
    cout << dp[n - 1][k + 1] << '\n';
    reverse(all(ans));
    for(int u : ans) cout << u + 1 << ' ';
}

int main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    #ifdef LOCAL
        freopen("input.txt", "r", stdin);
        //freopen("output.txt", "w", stdout);
    #endif
	int tt;
    //cin >> tt;
	tt = 1;
	while (tt--) {
        solve();
		//solve();
		#ifdef LOCAL
            cout << "__________________________________" << endl;
		#endif
	}
	#ifdef LOCAL
        cout << "finished in " << clock() * 1.0 / CLOCKS_PER_SEC << "sec" << '\n';
	#endif
	return 0;
}

• Subtask 1: 0 / 11
• Subtask 2: 11 / 11
• Subtask 3: 11 / 11
• Subtask 4: 17 / 17
• Subtask 5: 0 / 21
• Subtask 6: 0 / 29