Submission #633781

#	Time	Username	Problem	Language	Result	Execution time	Memory
633781		IWTIM	Copy and Paste 3 (JOI22_copypaste3)	C++14	30 / 100	376 ms	69448 KiB

copypaste3

# include <bits/stdc++.h>
using namespace std;
using ll = long long;
using db = long double; // or double, if TL is tight
using str = string; // yay python! 
 
// pairs
using pii = pair<int,int>;
using pl = pair<ll,ll>;
using pd = pair<db,db>;
#define mp make_pair
#define f first
#define s second
 
#define tcT template<class T
#define tcTU tcT, class U
// ^ lol this makes everything look weird but I'll try it
tcT> using V = vector<T>; 
tcT, size_t SZ> using AR = array<T,SZ>; 
using vi = V<int>;
using vb = V<bool>;
using vl = V<ll>;
using vd = V<db>;
using vs = V<str>;
using vpi = V<pii>;
using vpl = V<pl>;
using vpd = V<pd>;
 
// vectors
// oops size(x), rbegin(x), rend(x) need C++17
#define sz(x) int((x).size())
#define bg(x) begin(x)
#define all(x) bg(x), end(x)
#define rall(x) x.rbegin(), x.rend() 
#define sor(x) sort(all(x)) 
#define rsz resize
#define ins insert 
#define pb push_back
#define eb emplace_back
#define ft front()
#define bk back()
 
#define lb lower_bound
#define ub upper_bound
#define FOR(i,a,b) for (int i = (a); i < (b); ++i)
#define F0R(i,a) FOR(i,0,a)
#define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i)
#define R0F(i,a) ROF(i,0,a)
#define rep(a) F0R(_,a)
#define each(a,x) for (auto& a: x)
const int MOD = 998244353;
const int MX = 2e5+5;
const ll BIG = 1e18; // not too close to LLONG_MAX
const db PI = acos((db)-1);
const int dx[4]{1,0,-1,0}, dy[4]{0,1,0,-1}; // for every grid problem!!
mt19937 rng((uint32_t)chrono::steady_clock::now().time_since_epoch().count()); 
template<class T> using pqg = priority_queue<T,vector<T>,greater<T>>;
struct DSU {
	vi e; void init(int N) { e = vi(N,-1); }
	int get(int x) { return e[x] < 0 ? x : e[x] = get(e[x]); } 
	bool sameSet(int a, int b) { return get(a) == get(b); }
	int size(int x) { return -e[get(x)]; }
	bool unite(int x, int y) { // union by size
		x = get(x), y = get(y); if (x == y) return 0;
		if (e[x] > e[y]) swap(x,y);
		e[x] += e[y]; e[y] = x; return 1;
	}
};
/*
inline namespace Helpers {
	//////////// is_iterable
	// https://stackoverflow.com/questions/13830158/check-if-a-variable-type-is-iterable
	// this gets used only when we can call begin() and end() on that type
	tcT, class = void> struct is_iterable : false_type {};
	tcT> struct is_iterable<T, void_t<decltype(begin(declval<T>())),
	                                  decltype(end(declval<T>()))
	                                 >
	                       > : true_type {};
	tcT> constexpr bool is_iterable_v = is_iterable<T>::value;
 
	//////////// is_readable
	tcT, class = void> struct is_readable : false_type {};
	tcT> struct is_readable<T,
	        typename std::enable_if_t<
	            is_same_v<decltype(cin >> declval<T&>()), istream&>
	        >
	    > : true_type {};
	tcT> constexpr bool is_readable_v = is_readable<T>::value;
 
	//////////// is_printable
	// // https://nafe.es/posts/2020-02-29-is-printable/
	tcT, class = void> struct is_printable : false_type {};
	tcT> struct is_printable<T,
	        typename std::enable_if_t<
	            is_same_v<decltype(cout << declval<T>()), ostream&>
	        >
	    > : true_type {};
	tcT> constexpr bool is_printable_v = is_printable<T>::value;
}*/
using ll = long long;
using db = long double; // or double, if TL is tight
using str = string; // yay python! 
 
// pairs
using pii = pair<int,int>;
using pl = pair<ll,ll>;
using pd = pair<db,db>;
#define mp make_pair
#define f first
#define s second
 
#define tcT template<class T
#define tcTU tcT, class U
// ^ lol this makes everything look weird but I'll try it
tcT> using V = vector<T>; 
tcT, size_t SZ> using AR = array<T,SZ>; 
using vi = V<int>;
using vb = V<bool>;
using vl = V<ll>;
using vd = V<db>;
using vs = V<str>;
using vpi = V<pii>;
using vpl = V<pl>;
using vpd = V<pd>;
 
// vectors
// oops size(x), rbegin(x), rend(x) need C++17
#define sz(x) int((x).size())
#define bg(x) begin(x)
#define all(x) bg(x), end(x)
#define rall(x) x.rbegin(), x.rend() 
#define sor(x) sort(all(x)) 
#define rsz resize
#define ins insert 
#define pb push_back
#define eb emplace_back
#define ft front()
#define bk back()
 
#define lb lower_bound
#define ub upper_bound
#define FOR(i,a,b) for (int i = (a); i < (b); ++i)
#define F0R(i,a) FOR(i,0,a)
#define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i)
#define R0F(i,a) ROF(i,0,a)
#define rep(a) F0R(_,a)
#define each(a,x) for (auto& a: x)
template<class T> using pqg = priority_queue<T,vector<T>,greater<T>>;
 
/*
inline namespace Helpers {
	//////////// is_iterable
	// https://stackoverflow.com/questions/13830158/check-if-a-variable-type-is-iterable
	// this gets used only when we can call begin() and end() on that type
	tcT, class = void> struct is_iterable : false_type {};
	tcT> struct is_iterable<T, void_t<decltype(begin(declval<T>())),
	                                  decltype(end(declval<T>()))
	                                 >
	                       > : true_type {};
	tcT> constexpr bool is_iterable_v = is_iterable<T>::value;
 
	//////////// is_readable
	tcT, class = void> struct is_readable : false_type {};
	tcT> struct is_readable<T,
	        typename std::enable_if_t<
	            is_same_v<decltype(cin >> declval<T&>()), istream&>
	        >
	    > : true_type {};
	tcT> constexpr bool is_readable_v = is_readable<T>::value;
 
	//////////// is_printable
	// // https://nafe.es/posts/2020-02-29-is-printable/
	tcT, class = void> struct is_printable : false_type {};
	tcT> struct is_printable<T,
	        typename std::enable_if_t<
	            is_same_v<decltype(cout << declval<T>()), ostream&>
	        >
	    > : true_type {};
	tcT> constexpr bool is_printable_v = is_printable<T>::value;
}*/
#define int long long
const int N = 3005, mod = 998244353;
int t,n,a,b,c,nxt[N], dp[N][N],pw[N];
vector < pii > v;
int hs[N][N];
string s;
int get(char ch) {
	return (ch - 'a' + 1);
}
void go(vector <int> vv, int sz) {
	int cur = -1;
	for (int i = (int)vv.size() - 1; i >= 0; i--) {
	    //cout<<vv[i]<<" ";
		while(true) {
			if (vv.back() >= vv[i] + sz) {
				cur = vv.back();
				vv.pop_back();
			} else break;
		}
		nxt[vv[i]] = cur;
	}
}
main() {
    cin>>n>>s>>a>>b>>c;
    s = "@" + s;
    for (int i = 1; i <= n; i++) {
    	for (int j = i; j <= n; j++) {
    		dp[i][j] = (j - i + 1)*a;
		}
	}
	int p = 37;
	pw[0] = 1;
	for (int i = 1; i <= n; i++) {
		pw[i] = (pw[i - 1] * p) % mod;
	}
	for (int i = 1; i <= n; i++) {
		int curhs = 0;
		for (int j = i; j <= n; j++) {
			curhs = (curhs + pw[j - i] * get(s[j])) % mod;  
			hs[i][j] = curhs;
		}
	}
	for (int sz = 1; sz <= n; sz++) {
		v.clear();
		for (int j = 1; j + sz - 1 <= n; j++) {
			v.pb({hs[j][j + sz - 1], j});
		}
		v.pb({mod, 0});
		sort(v.begin(),v.end());
		int le = 0;
		for (int i = 1; i < v.size(); i++) {
			if (v[i].f != v[i - 1].f) {
				int ri = i - 1;
				vector <int> vv;
				for (int j = le; j <= ri; j++) {
					vv.pb(v[j].s);
				}
				go(vv,sz);
				le = i;
			}
		}
		
		for (int l = 1; l + sz - 1 <= n; l++) {
			if (sz > 1) dp[l][l + sz - 1] = min(dp[l][l + sz - 1], min(dp[l + 1][l + sz - 1] + a, dp[l][l + sz - 2] + a)); 
		}
		for (int l = 1; l + sz - 1 <= n; l++) {
			int curl = l;
			int cnt = 1;
			while (nxt[curl] != -1) {
				cnt++;
				int ri = nxt[curl] + sz - 1;
				dp[l][nxt[curl] + sz - 1] = min(dp[l][nxt[curl] + sz - 1], dp[l][l + sz - 1] + b + cnt * c + (ri - l + 1 - sz * cnt)*a);
			    curl = nxt[curl];
			}
		}
	}
	cout<<dp[1][n]<<"\n";
}

Compilation message (stderr)

copypaste3.cpp:203:1: warning: ISO C++ forbids declaration of 'main' with no type [-Wreturn-type]
  203 | main() {
      | ^~~~
copypaste3.cpp: In function 'int main()':
copypaste3.cpp:231:21: warning: comparison of integer expressions of different signedness: 'long long int' and 'std::vector<std::pair<int, int>, std::allocator<std::pair<int, int> > >::size_type' {aka 'long unsigned int'} [-Wsign-compare]
  231 |   for (int i = 1; i < v.size(); i++) {
      |                   ~~^~~~~~~~~~

• Subtask 1: 1 / 1
• Subtask 2: 5 / 5
• Subtask 3: 14 / 14
• Subtask 4: 10 / 10
• Subtask 5: 0 / 32
• Subtask 6: 0 / 38