This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<bits/stdc++.h>
using namespace std;
mt19937 rnd(51);
#define ll long long
#define pb push_back
#define ld long double
int n, m, INF;
vector<vector<int>> a, any;
vector<pair<int,int>> d{{-1, 0}, {0, 1}, {1, 0}, {0, -1}};
vector<bool> used(4);
vector<vector<vector<int>>> side, two;
bool check(int i, int j) {
return i >= 0 && i < n && j >= 0 && j < m;
}
int get_max(int i, int j, vector<int> ban = {}) {
int mx = -1;
for (auto to : ban) {
used[to] = 1;
}
for (int k = 0; k < 4; k++) {
if (used[k]) {
continue;
}
int x = i + d[k].first, y = j + d[k].second;
if (check(x, y) && a[x][y] < a[i][j]) {
mx = max(mx, a[x][y]);
}
}
for (auto to : ban) {
used[to] = 0;
}
return (mx == -1 ? 0 : a[i][j] - mx);
}
void build() {
int h = max(n, m), w = min(n, m);
a.resize(h);
any.resize(h);
side.resize(h);
two.resize(h);
for (int i = 0; i < h; i++) {
a[i].resize(w);
any[i].resize(w);
side[i].resize(w);
two[i].resize(w);
}
for (int i = 0; i < h; i++) {
for (int j = 0; j < w; j++) {
side[i][j].resize(4);
two[i][j].resize(4);
}
}
}
// 0 -> U
// 1 -> R
// 2 -> D
// 3 -> L
signed main() {
#ifdef LOCAL
freopen("input.txt", "r", stdin);
#endif // LOCAL
ios_base::sync_with_stdio(0);
cin.tie(0);
cin >> n >> m;
INF = n * m;
build();
if (n < m) {
swap(n, m);
for (int j = 0; j < m; j++) {
for (int i = 0; i < n; i++) {
cin >> a[i][j];
}
}
} else {
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
cin >> a[i][j];
}
}
}
ll ans = 0;
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
any[i][j] = get_max(i, j);
for (int k = 0; k < 4; k++) {
side[i][j][k] = get_max(i, j, {k});
two[i][j][k] = get_max(i, j, {k, (k + 1) % 4});
}
}
}
for (int i = 0; i < n; i++) {
int last = 2, cnt = 0;
for (int j = 1; j < m; j++) {
if ((last ^ (a[i][j - 1] < a[i][j])) == 1) {
ans += 1ll * cnt * (cnt + 1) / 2;
cnt = 1;
} else {
cnt++;
}
last = (a[i][j - 1] < a[i][j]);
}
ans += cnt * (cnt + 1) / 2;
}
for (int j = 0; j < m; j++) {
int last = 2, cnt = 0;
for (int i = 1; i < n; i++) {
if ((last ^ (a[i - 1][j] < a[i][j])) == 1) {
ans += 1ll * cnt * (cnt + 1) / 2;
cnt = 1;
} else {
cnt++;
}
last = (a[i - 1][j] < a[i][j]);
}
ans += cnt * (cnt + 1) / 2;
}
ans += n * m;
cout << ans << endl;
return 0;
}
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