#include <bits/stdc++.h>
using namespace std;
#define MOD 1000000007
#define ll long long int
#define vi vector<int>
#define vii vector< vector<int> >
#define PI 3.1415926535897932384626433832795
#define INF 9223372036854775807LL
bool solved[51][20001];
int dp[20001][51];
int minval[20002][52][52];
int prefsum[20002];
int conssolved[51][20001]; //[x][y]=z means, the xth solved y-z+1,y-z+2,...,y tasks but not the y-z th
int main() {
ios::sync_with_stdio(false);
cin.tie(NULL);
int n,t,s;
cin >> n >> t >> s;
vi p(t+1);
for(int i = 1; i <= t; i++) {
cin >> p[i];
prefsum[i] = prefsum[i-1]+p[i];
}
for(int i = 1; i <= n; i++) {
int lastnotsolv = 0;
for(int j = 1; j <= t; j++) {
char ch;
cin >> ch;
solved[i][j] = (ch == '1');
if(!solved[i][j]) {
lastnotsolv = j;
}
conssolved[i][j] = j-lastnotsolv;
}
}
int sum = 0;
for(int j = 0; j <= s; j++) {
for(int i = 0; i <= t; i++) {
for(int per = 0; per <= n; per++) {
minval[i][j][per] = 2*MOD;
}
}
}
for(int i = 1; i <= t; i++) {
sum+= p[i];
int solv = 0;
for(int j = 1; j <= n; j++) {
if(conssolved[j][i] == i) {
solv++;
}
}
dp[i][1] = solv*sum;
for(int pers = 0; pers <= n; pers++) {
minval[i][2][pers] = min(minval[i-1][2][pers]+pers*p[i],dp[i][1]);
}
//cout << (dp[i][1] > MOD ? -1 : dp[i][1]) << " ";
}
//cout << endl;
for(int j = 2; j <= s; j++) {
for(int i = 1; i <= t; i++) {
dp[i][j] = 2*MOD;
sum = 0;
vector<int> solves;
for(int st = 1; st <= n; st++) {
solves.push_back(conssolved[st][i]);
}
sort(solves.begin(),solves.end());
int ind = 0;
for(int currsiz : solves) {
currsiz++;
if(currsiz < 1) {
continue;
}
if(currsiz > i-j+1) {
break;
}
while(ind < n && solves[ind] < currsiz) {
ind++;
}
sum = prefsum[i]-prefsum[i-currsiz];
//sum+= p[i-currsiz+1];
if(dp[i][j] == dp[i][j-1]) {
break;
}
// if(ind == n) {
dp[i][j] = min(dp[i][j],minval[i-currsiz][j][n-ind]+sum*(n-ind));
// if(j == 3 && minval[i-currsiz][j][n-ind]+sum*(n-ind) == 0) {
// cout << i << " " << currsiz << " " << ind << endl;
// }
// break;
//}
}
for(int pers = 0; pers <= n; pers++) {
minval[i][j+1][pers] = min(minval[i-1][j+1][pers]+pers*p[i],dp[i][j]);
}
//cout << (dp[i][j] > MOD ? -1 : dp[i][j]) << " ";
//cout << i << " " << j << " " << dp[i][j] << endl;
}
// cout << endl;
}
for(int i = 1; i <= s; i++) {
cout << dp[t][i] << "\n";
}
return 0;
}
| # |
Verdict |
Execution time |
Memory |
Grader output |
| 1 |
Correct |
2 ms |
376 KB |
Output is correct |
| 2 |
Incorrect |
4 ms |
1080 KB |
Output isn't correct |
| # |
Verdict |
Execution time |
Memory |
Grader output |
| 1 |
Incorrect |
98 ms |
6308 KB |
Output isn't correct |
| 2 |
Halted |
0 ms |
0 KB |
- |
| # |
Verdict |
Execution time |
Memory |
Grader output |
| 1 |
Incorrect |
386 ms |
25128 KB |
Output isn't correct |
| 2 |
Halted |
0 ms |
0 KB |
- |
| # |
Verdict |
Execution time |
Memory |
Grader output |
| 1 |
Correct |
2 ms |
376 KB |
Output is correct |
| 2 |
Incorrect |
4 ms |
1080 KB |
Output isn't correct |
