Submission #630809

#TimeUsernameProblemLanguageResultExecution timeMemory
630809codr0Mergers (JOI19_mergers)C++14
10 / 100
29 ms35972 KiB
#include <bits/stdc++.h>
#define ll long long
#define pll pair<ll,ll>
#define pii pair<int,int>

#define FOR(i,a,b) for(int i=a;i<=b;i++)
#define FORR(i,a,b) for(int i=a;i>=b;i--)
#define F first
#define S second
#define err(x) cerr<<#x<<" : "<<x<<'\n';
#define dmid int mid=(r+l)/2
#define lc 2*id
#define rc 2*id+1
#define pb push_back
#define all(x) x.begin(),x.end()
#define SZ(x) (int)x.size()
#define maxm(a,b) a=max(a,b)
#define minm(a,b) a=min(a,b)

using namespace std;
const int N=3000+4;
vector<int> adj[N];
int cnt[N];
int t[N][N],dp[N];
int n,k;

	void dfs(int v,int p){
		for(int u:adj[v]) if(u!=p){
			dfs(u,v);
			dp[v]+=dp[u];
			FOR(j,1,k) t[v][j]+=t[u][j];
		}
		if(dp[v]==0&&v!=p){
			dp[v]=1;
			FOR(j,1,k) if(t[v][j]!=cnt[j]&&t[v][j]!=0) dp[v]=0;
		}
	}

	int main(){
	iostream::sync_with_stdio(0); cin.tie(0);

	cin>>n>>k;
	FOR(_,1,n-1){
		int u,v; cin>>u>>v;
		adj[u].pb(v);
		adj[v].pb(u);
	}
	if(n<=2){
		int w0,w1; cin>>w0;
		if(n==1){
			cout<<"0\n";
			return 0;
		}
		if(n==2){
			cin>>w1;
			cout<<(w0!=w1)<<'\n';
			return 0;
		}
		assert(1==2);
	}
	FOR(i,1,n){
		int w; cin>>w;
		t[i][w]++;
		cnt[w]++;
	}
	int root=1;
	FOR(i,1,n) if(SZ(adj[i])>1) root=i;
	dfs(root,root);
	cout<<(dp[root]/2+(dp[root]&1))<<'\n';

	return 0;
	}
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