Submission #630380

#	Time	Username	Problem	Language	Result	Execution time	Memory
630380		amunduzbaev	Catfish Farm (IOI22_fish)	C++17	35 / 100	1094 ms	112392 KiB

fish

#include "fish.h"
#include "bits/stdc++.h"
using namespace std;

typedef long long ll;

#ifndef EVAL
#include "grader.cpp"
#endif

const int N = 3005;
vector<int> id[N];
int sz[N], pre[N];
ll pref[N][N], suff[N][N], mx[N][N];
ll tmp[N][N], P[N][N];

ll max_weights(int n, int m, vector<int> x, vector<int> y, vector<int> w) {
	for(int i=0;i<m;i++){
		x[i]++, y[i]++;
		if(x[i] > 1) id[x[i] - 1].push_back(y[i]);
		if(x[i] < n) id[x[i] + 1].push_back(y[i]);
		id[x[i]].push_back(y[i]);
		P[x[i]][y[i]] += w[i];
	}
	
	for(int i=1;i<=n;i++){
		for(int j=1;j<=n;j++){
			P[i][j] += P[i][j-1];
		}
	}
	
	for(int i=0;i<N;i++){
		id[i].push_back(0);
		sort(id[i].begin(), id[i].end());
		id[i].erase(unique(id[i].begin(), id[i].end()), id[i].end());
	}
	sz[0] = 1;
	
	for(int i=1;i<=n;i++){
 		sz[i] = id[i-1].size();
		for(int j_=0;j_<(int)id[i].size();j_++){ int j = id[i][j_];
			int pos, p2;
			if(i > 1){
				p2 = pos = lower_bound(id[i-2].begin(), id[i-2].end(), j) - id[i-2].begin();
				if(pos < sz[i-1] && id[i-2][pos] == j) p2++;
			} else {
				pos = 0;
				p2 = 1;
			}
			for(int k_ = 0; k_ < sz[i]; k_++){ int k = id[i-1][k_];
				tmp[j_][k_] = 0;
				ll s = P[i-1][j] + P[i+1][j] - (i > 1 ? P[i][min(j, k)] : 0);
				if(j <= k){
					tmp[j_][k_] = max(tmp[j_][k_], pref[k_][sz[i-1] - 1] + s - P[i-1][j]);
				} else {
					tmp[j_][k_] = max(tmp[j_][k_], pref[k_][pre[k_] - 1] + s - P[i-1][k]);
					if(pos < sz[i-1]) tmp[j_][k_] = max(tmp[j_][k_], suff[k_][pos] + s - P[i-1][j]);
					if(p2) tmp[j_][k_] = max(tmp[j_][k_], mx[k_][p2 - 1] + s);
				}
			}
		}
		
		for(int j=0;j<(int)id[i].size();j++){
			pre[j] = lower_bound(id[i - 1].begin(), id[i - 1].end(), id[i][j]) - id[i - 1].begin();
			for(int k=0;k<sz[i];k++){
				pref[j][k] = suff[j][k] = mx[j][k] = tmp[j][k];
				mx[j][k] -= P[i][id[i-1][k]];
				if(k) pref[j][k] = max(pref[j][k], pref[j][k-1]);
				if(k > pre[j]) mx[j][k] = max(mx[j][k-1], mx[j][k]);
			}
			suff[j][sz[i]] = 0;
			for(int k=sz[i]-1;k>=0;k--){
				suff[j][k] = max(suff[j][k+1], suff[j][k]);
			}
			if(pre[j] < sz[i] && id[i-1][pre[j]] == id[i][j]) pre[j]++;
		}
	}
	
	ll res = 0;
	for(int i=0;i<(int)id[n].size();i++){
		for(int j=0;j<sz[n];j++){
			res = max(res, tmp[i][j]);
		}
	}
	
	return res;
}

/*

5 4
0 2 5
1 1 2
4 4 1
3 3 3

5 6
2 3 3
2 1 2
4 1 3
2 0 10
4 4 1
4 0 7

*/

• Subtask 1: 0 / 3
• Subtask 2: 0 / 6
• Subtask 3: 0 / 9
• Subtask 4: 14 / 14
• Subtask 5: 21 / 21
• Subtask 6: 0 / 17
• Subtask 7: 0 / 14
• Subtask 8: 0 / 16