Submission #622731

#	Time	Username	Problem	Language	Result	Execution time	Memory
622731		Dremix10	Sky Walking (IOI19_walk)	C++17	10 / 100	4038 ms	1048576 KiB

walk

#include "walk.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int,int> pi;
typedef pair<ll,ll> pl;
#define F first
#define S second
#define all(x) (x).begin(),(x).end()
#ifdef dremix
    #define p(x) cerr<<#x<<" = "<<x<<endl;
    #define p2(x,y) cerr<<#x<<" , "<<#y<<" = "<<x<<" , "<<y<<endl;
    #define pp(x) cerr<<#x<<" = "<<x.F<<"-"<<x.S<<endl;
    #define pv(x) cerr<<#x<<" = {";for(auto v : x)cerr<<v<<", ";cerr<<"}"<<endl;
    #define ppv(x) cerr<<#x<<" = {";for(auto v : x)cerr<<v.F<<"-"<<v.S<<", ";cerr<<"}"<<endl;
#else
    #define p(x) {}
    #define p2(x,y) {}
	#define pp(x) {}
    #define pv(x) {}
    #define ppv(x) {}
#endif
const int N = 3e5+5;
const int MOD = 1e9+7;
const ll INF = 1e18+5;

struct ano{
	int x,bef;
	ll d;

	bool operator<(const ano &x)const{
		return d > x.d;
	}
};


long long min_distance(vector<int> x, vector<int> h, vector<int> l, vector<int> r, vector<int> y, int s, int g) {
	int n = x.size();
	int m = l.size();

	vector<vector<int> > a(n+m);

	int i,j;
	//int cnt[n+m] = {};

	for(i=0;i<n;i++){

		for(j=0;j<m;j++){
			if(l[j] <= i && i <= r[j] && h[i] >= y[j]){
				a[i].push_back(n+j);
				a[n+j].push_back(i);
				/*
				cnt[i] ++;
				cnt[]
				*/
			}
		}

	}

	priority_queue<ano> q;
	q.push({s,n+m,0});
	
	vector<vector<ll> > d(n+m+1,vector<ll>(n+m+1,INF));

	/*
	for(i=0;i<n;;i++){
		d[i].assign(cnt[i],INF);
	}
	for(i=n;i<n+m;i++){
		d[i].assign(1,INF);
	}
	*/
	d[s][n+m] = 0;
	y.push_back(0);

	

	while(!q.empty()){
		ano temp = q.top();
		q.pop();

		bool sky = false;
		if(temp.x >= n)sky = true;

		if(temp.d > d[temp.x][temp.bef])continue;
		p2(temp.x,temp.bef)
		p(temp.d)
		for(auto v : a[temp.x]){
			ll cost;
			if(sky)
				cost = abs(x[temp.bef] - x[v]);
			else
				cost = abs(y[temp.bef-n] - y[v-n]);
			if(d[v][temp.x] > d[temp.x][temp.bef] + cost){
				d[v][temp.x] = d[temp.x][temp.bef] + cost;
				q.push({v,temp.x,d[v][temp.x]});
			}
		}
	}

	for(i=n;i<n+m;i++){
		d[g][g] = min(d[g][g],d[g][i]+y[i-n]);
	}
	if(d[g][g] == INF)d[g][g] = -1;
	return d[g][g];
}

• Subtask 1: 10 / 10
• Subtask 2: 0 / 14
• Subtask 3: 0 / 15
• Subtask 4: 0 / 18
• Subtask 5: 0 / 43