Submission #62250

#	Time	Username	Problem	Language	Result	Execution time	Memory
62250		Benq	Binary Subsequences (info1cup17_binary)	C++11	82 / 100	1075 ms	736 KiB

binary

#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>

using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;

typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;

typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;

template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;

#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)

#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()

const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 100001;

bool ok[10][10];

void brute() {
    ok[0][0] = 1;
    F0R(i,10) {
        F0R(j,10) {
            // cout << ok[i][j];
            if (ok[i][j]) cout << i << " " << j << "\n";
            if (ok[i][j] && i+j+1 < 10) ok[i+j+1][j] = ok[i][i+j+1] = 1;
        }
        cout << "\n";
    }
}

int K;

int get(int a, int b) { // a >= b
    if (a == b) {
        if (a != 1) return MOD;
        return 0;
    }
    int mul = (a-1)/b;
    return mul+get(b,a-mul*b);
}

void GET(int l, int r) {
    if (l == r) return;
    if (l > r) {
        int mul = (l-1)/r;
        GET(l-mul*r,r);
        F0R(i,mul) cout << "0 ";
    } else {
        int mul = (r-1)/l;
        GET(l,r-mul*l);
        F0R(i,mul) cout << "1 ";
    }
}

void solve() {
    cin >> K;
    int ans = 0;
    pi bes = {MOD,MOD};
    F0R(i,K+1) {
        int x = get(max(i+1,K-i+1),min(i+1,K-i+1));
        bes = min(bes,{x,i});
        if (x < MOD) ans ++;
    }
    cout << ans << "\n";
    GET(bes.s+1,K-bes.s+1);
    cout << "\n";
}

int main() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    int T; cin >> T;
    F0R(i,T) solve();
}

/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/

• Subtask 1: 43 / 43
• Subtask 2: 39 / 39
• Subtask 3: 0 / 18