Submission #622406

#	Time	Username	Problem	Language	Result	Execution time	Memory
622406		Ferid20072020	Autići (COCI22_autici)	C++14	10 / 50	14 ms	1332 KiB

Main

#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")


#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>



using namespace __gnu_pbds;
using namespace std;
using namespace chrono;
// using namespace atcoder



#define YES             cout << "YES"
#define NO              cout << "NO"
#define fd              fixed
#define ll              long long
#define ull             unsigned long long
#define ui              unsigned int
#define dbl             double
#define ld              long double
#define f               first
#define s               second
#define pii             pair<int , int>
#define pll             pair<ll , ll>
#define pil             pair<int , ll>
#define pli             pair<ll , int>
#define psi             pair<string , int>
#define pci             pair<char , int>
#define pic             pair<int , char>
#define pis             pair<int , string>
#define psl             pair<string , ll>
#define pcl             pair<char , ll>
#define plc             pair<ll , char>
#define pls             pair<ll , string>
#define pb              push_back
#define eb              emplace_back
#define mp              make_pair
#define ins             insert
#define END             return 0
#define speed           ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#define all(x)          (x).begin() , (x).end()
#define oo              1e9


/*
int gcd(int number1 , int number2){
   if(number2 == 0){
      return number1;
   }
   return gcd(number2 , number1 % number2);
}

int lcm(int number1 , int number2){
   return number1 / gcd(number1 , number2) * number2;
}

ll fact(int number){
   ll product = 1;
   for(int i=2 ; i<=number ; i++){
      product *= i;
   }
   return product;
}
*/


#define int ll



void solve(){
   int n;
   cin >> n;
   int d;
   cin >> d;
   int ans = 0;
   for(int i=1 ; i<n ; i++){
      int x;
      cin >> x;
      ans += d + x;
      d = x;
   }
   cout << ans;
}


signed  main(){
   speed;

   int t = 1;
   //cin >> t;

   while(t--){
      solve();
   }

   END;
}

• Subtask 1: 10 / 10
• Subtask 2: 0 / 20
• Subtask 3: 0 / 20