Submission #621403

#TimeUsernameProblemLanguageResultExecution timeMemory
621403abcisosm5Mecho (IOI09_mecho)C++17
84 / 100
801 ms2876 KiB
#include <bits/stdc++.h> using namespace std; #define pi pair<int, int> #define f first #define s second int N, S; const int MN = 800; char grid[MN][MN] = {{}}; vector<pi> hives; pi M; pi D; int dx[4] = {1, -1, 0, 0}; int dy[4] = {0, 0, 1, -1}; void movebees(queue<pi> (&b), char (&v)[MN][MN], int t){ for(int i = 0; i < t; i++){ queue<pi> nextb; while(!b.empty()){ pi p = b.front(); b.pop(); for(int d = 0; d < 4; d++){ int nx = p.f + dx[d]; int ny = p.s + dy[d]; if(nx < 0 || nx >= N || ny < 0 || ny >= N) continue; if(v[nx][ny] != 'B' && grid[nx][ny] == 'G'){ v[nx][ny] = 'B'; nextb.push({nx, ny}); } } } b = nextb; } } bool movemecho(queue<pi> (&m), char (&v)[MN][MN]){ for(int i = 0; i < S; i++){ queue<pi> nextm; while(!m.empty()){ pi p = m.front(); m.pop(); if(v[p.f][p.s] == 'B') continue; //invalidate positions that are now occupied by bees for(int d = 0; d < 4; d++){ int nx = p.f + dx[d]; int ny = p.s + dy[d]; if(nx < 0 || nx >= N || ny < 0 || ny >= N) continue; if(!v[nx][ny] && grid[nx][ny] != 'T'){ v[nx][ny] = 'M'; if(grid[nx][ny] == 'D') return true; nextm.push({nx, ny}); } } } m = nextm; } return false; } bool works(int t){ //O(N^2) char visited[MN][MN] = {{}}; queue<pi> bees; for(pi p : hives){ bees.push(p); visited[p.first][p.second] = 'B'; } movebees(bees, visited, t); queue<pi> mecho; mecho.push(M); visited[M.f][M.s] = 'M'; for(int i = 0; i < N*N/2; i++){ //first, move mecho S steps if(mecho.empty()) break; bool success = movemecho(mecho, visited); if(success) return true; //then, move bees 1 step movebees(bees, visited, 1); } return false; } int main(){ cin.tie(0)->sync_with_stdio(0); cin >> N >> S; for(int i = 0; i < N; i++){ for(int j = 0; j < N; j++){ cin >> grid[i][j]; if(grid[i][j] == 'M') M = {i, j}; if(grid[i][j] == 'D') D = {i, j}; if(grid[i][j] == 'H') hives.push_back({i,j}); } } int lo = -1; int hi = N*N/2; //amount of head start to bees while(lo < hi){ // in total, O(N^2 log N) int mid = lo + (hi - lo + 1) / 2; if(works(mid)){ lo = mid; } else { hi = mid - 1; } } cout << lo; }
#Verdict Execution timeMemoryGrader output
Fetching results...