Submission #61861

#TimeUsernameProblemLanguageResultExecution timeMemory
61861BenqMaxcomp (info1cup18_maxcomp)C++11
100 / 100
244 ms76012 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/assoc_container.hpp> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef complex<ld> cd; typedef pair<int, int> pi; typedef pair<ll,ll> pl; typedef pair<ld,ld> pd; typedef vector<int> vi; typedef vector<ld> vd; typedef vector<ll> vl; typedef vector<pi> vpi; typedef vector<pl> vpl; typedef vector<cd> vcd; template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; #define FOR(i, a, b) for (int i=a; i<(b); i++) #define F0R(i, a) for (int i=0; i<(a); i++) #define FORd(i,a,b) for (int i = (b)-1; i >= a; i--) #define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--) #define sz(x) (int)(x).size() #define mp make_pair #define pb push_back #define f first #define s second #define lb lower_bound #define ub upper_bound #define all(x) x.begin(), x.end() const int MOD = 1000000007; const ll INF = 1e18; const int MX = 100001; int N,M; ll ans = -INF, A[1000][1000], bes[1000][1000]; ll solve() { ll ret = -INF; F0Rd(i,N) F0Rd(j,M) { bes[i][j] = -INF; if (i < N-1) bes[i][j] = max(bes[i][j],bes[i+1][j]); if (j < M-1) bes[i][j] = max(bes[i][j],bes[i][j+1]); bes[i][j] = max(bes[i][j],A[i][j]-i-j); ret = max(ret,bes[i][j]-A[i][j]+i+j-1); } return ret; } int main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> N >> M; F0R(i,N) F0R(j,M) cin >> A[i][j]; ans = solve(); F0R(i,N) for (int j = 0; j < M-1-j; ++j) swap(A[i][j],A[i][M-1-j]); ans = max(ans,solve()); for (int i = 0; i < N-1-i; ++i) F0R(j,M) swap(A[i][j],A[N-1-i][j]); ans = max(ans,solve()); F0R(i,N) for (int j = 0; j < M-1-j; ++j) swap(A[i][j],A[i][M-1-j]); ans = max(ans,solve()); cout << ans; } /* Look for: * the exact constraints (multiple sets are too slow for n=10^6 :( ) * special cases (n=1?) * overflow (ll vs int?) * array bounds */
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