Submission #617896

#	Time	Username	Problem	Language	Result	Execution time	Memory
617896		MohamedAliSaidane	Rainforest Jumps (APIO21_jumps)	C++14	4 / 100	911 ms	4012 KiB

jumps

#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include "jumps.h"
        using namespace __gnu_pbds;
        using namespace std;

        typedef tree<int,null_type,less<int>,rb_tree_tag,
        tree_order_statistics_node_update> indexed_set;

        typedef long long ll;
        typedef long double ld;

        //#define int ll

        typedef pair<int,int> pii;
        typedef pair<ll,ll> pll;
        typedef pair<ld,ld> pld;

        typedef vector<int> vi;
        typedef vector<ll> vll;
        typedef vector<pii> vpi;
        typedef vector<pll> vpl;

        #define pb push_back
        #define popb pop_back
        #define pp pop_back
        #define pf push_front
        #define popf pop_front
        #define all(x) (x).begin(),(x).end()
        #define ff first
        #define ss second



        int nx[4] = {0,0,1,-1}, ny[4] = {1,-1,0,0};
        ll gcd(ll a , ll b) {return b ? gcd(b , a % b) : a ;}
        ll lcm(ll a , ll b) {return (a * b) / gcd(a , b);}


        const ll MOD =   998244353;

        int n;
        vll A;
        const int nax = 2e5 + 4;
        ll sp[nax][20];
        int LG[nax];
        int L[nax], R[nax];
        void build()
        {
            for(int i = 0; i < n; i++)
                sp[i][0] = A[i];
            for(int j = 1; j < 20; j++)
                for(int i=  0; i + (1 << j) <= n; i ++)
                    sp[i][j] = max(sp[i][j-1],sp[i + (1 << (j-1))][j - 1]);
        }
        int rmq(int l, int r)
        {
            int j = LG[r - l + 1];
            return max(sp[l][j], sp[r - (1 << j) + 1][j]);
        }
        void init(int N, vi H)
        {
            n = N;
            for(int i = 0 ; i < n;i ++)
                A.pb(H[i]);
        }
        int minimum_jumps(int a, int b, int c, int d)
        {
            if(d < a)
                return -1;
            if(c >= a && c <= b)
                return 0;
            if(a >= c && a <= d)
                return 0;
            return  c - b;
        }

• Subtask 1: 4 / 4
• Subtask 2: 0 / 8
• Subtask 3: 0 / 13
• Subtask 4: 0 / 12
• Subtask 5: 0 / 23
• Subtask 6: 0 / 21
• Subtask 7: 0 / 19