Submission #617752

#	Time	Username	Problem	Language	Result	Execution time	Memory
617752		SavicS	Carnival (CEOI14_carnival)	C++17	100 / 100	24 ms	448 KiB

carnival

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <bits/stdc++.h>
 
using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ldb;
 
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef pair<ldb,ldb> pdd;

#define ff(i,a,b) for(int i = a; i <= b; i++)
#define fb(i,b,a) for(int i = b; i >= a; i--)
#define trav(a,x) for(auto& a : x)
 
#define sz(a) (int)(a).size()
#define fi first
#define se second
#define pb push_back
#define lb lower_bound
#define ub upper_bound
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
 
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

template<typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

// os.order_of_key(k) the number of elements in the os less than k
// *os.find_by_order(k)  print the k-th smallest number in os(0-based)

const int mod = 1000000007;
const int inf = 1e9 + 5;
const int mxN = 155; 

int n;

int res[mxN];

int pref[mxN];
int sufi[mxN];

int ask(vector<int> A){
    cout << sz(A) << " "; 
    for(auto c : A)cout << c << " ";
    cout << endl;
    
    int X;
    cin >> X;
    return X;
}

int main() {
    cin.tie(0)->sync_with_stdio(0);

    cin >> n;

    vector<int> vec, A;

    int idx = 0; int pre = 0;
    ff(i,1,n){
        vec.pb(i); int sad = ask(vec);

        if(sad != pre){
            res[i] = ++idx;
            A.pb(i);
        }
        
        pre = sad;

    }

    ff(i,1,n){
        if(res[i] == 0){

            for(auto c : A){
                if(ask({i, c}) == 1){
                    res[i] = res[c];
                    break;
                }
            }

        }
    }

    cout << 0 << " ";
    ff(i,1,n)cout << res[i] << " ";
    cout << endl;

    return 0;
}
/*



// probati bojenje sahovski
*/
 
 
 
 
 

• Subtask 1: 20 / 20
• Subtask 2: 20 / 20
• Subtask 3: 20 / 20
• Subtask 4: 20 / 20
• Subtask 5: 20 / 20