Submission #608794

#TimeUsernameProblemLanguageResultExecution timeMemory
608794generic_placeholder_namePopeala (CEOI16_popeala)C++17
100 / 100
330 ms17764 KiB
#pragma GCC optimize("Ofast") #pragma GCC optimize("unroll-loops") #pragma GCC target("avx,avx2,fma,popcnt") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/trie_policy.hpp> #include <ext/rope> using namespace std; using namespace __gnu_pbds; using namespace __gnu_cxx; mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()); #define fi first #define se second #define pb push_back #define eb emplace_back #define mp make_pair #define gcd __gcd #define fastio ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0) #define rep(i, n) for (int i=0; i<(n); i++) #define rep1(i, n) for (int i=1; i<=(n); i++) #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() #define endl "\n" typedef long long ll; typedef unsigned long long ull; typedef unsigned uint; typedef long double ld; typedef pair<int, int> pii; typedef pair<ll, ll> pll; typedef vector<int> vi; typedef vector<vector<int>> vvi; typedef vector<ll> vll; typedef vector<vector<ll>> vvll; typedef vector<bool> vb; typedef vector<vector<bool>> vvb; template<typename T, typename cmp = less<T>> using ordered_set = tree<T, null_type, cmp, rb_tree_tag, tree_order_statistics_node_update>; typedef trie<string, null_type, trie_string_access_traits<>, pat_trie_tag, trie_prefix_search_node_update> pref_trie; constexpr int N = 55, T = 20005; constexpr ll INF = 0x3f3f3f3f3f3f3f3f; ll dp[T][N], a[T], prv[T][N], best[N]; int32_t main() { fastio; int n, t, s; cin >> n >> t >> s; rep1(i, t) cin >> a[i], a[i] += a[i - 1]; rep1(i, n) { string s; cin >> s; rep(j, t) prv[j + 1][i] = s[j] == '1' ? prv[j][i] : j + 1; } rep1(i, t) { prv[i][0] = i; sort(prv[i], prv[i] + n + 1); } memset(dp, 0x3f, sizeof(dp)); dp[0][0] = 0; rep1(i, s) { rep(j, n + 1) best[j] = INF; rep1(j, t) rep(k, n + 1) { for(int l = prv[j - 1][k]; l < prv[j][k]; l++) best[k] = min(best[k], dp[l][i - 1] - a[l] * k); dp[j][i] = min(dp[j][i], best[k] + a[j] * k); } cout << dp[t][i] << endl; } }
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