Submission #608761

#TimeUsernameProblemLanguageResultExecution timeMemory
608761l_rehoValley (BOI19_valley)C++14
36 / 100
96 ms262144 KiB
#include<bits/stdc++.h> using namespace std; #define ll long long int N, S, Q, E; vector<vector<pair<int, ll>>> graph; vector<int> shops; vector<pair<int, int>> edges; vector<int> tin; vector<int> tout; map<int, bool> isShop; vector<vector<ll>> dist; int timer = 0; void dfs(int curr, int p){ tin[curr] = timer++; vector<pair<int, ll>> adj = graph[curr]; for(pair<int, ll> a : adj){ if(a.first == p) continue; dfs(a.first, curr); } tout[curr]=timer++; } bool inst(int a, int b){ return tin[a] <= tin[b] && tout[a] >= tout[b]; } void bfs(vector<int> starts){ queue<pair<int, int>> q; for(int s : starts){ q.push({s, s}); dist[s][s] = 0; } while(!q.empty()){ pair<int, int> curr = q.front(); q.pop(); int s = curr.first; int node = curr.second; vector<pair<int, ll>> adj = graph[node]; for(pair<int, ll> a : adj){ if(isShop[a.first]) continue; if(dist[s][a.first] != LLONG_MAX) continue; dist[s][a.first] = dist[s][node]+a.second; q.push({s, a.first}); } } } void solve(){ cin>>N>>S>>Q>>E; graph.assign(N+1, vector<pair<int, ll>>()); shops.assign(S, 0); tin.assign(N+1, 0); tout.assign(N+1, 0); edges.assign(N-1, pair<int, int>()); dist.assign(N+1, vector<ll>(N+1, LLONG_MAX)); for(int i = 0; i < N-1; i++){ int a, b, c; cin>>a>>b>>c; edges[i] = {a, b}; graph[a].push_back({b, c}); graph[b].push_back({a, c}); } for(int i = 0; i < S; i++){ cin>>shops[i]; isShop[shops[i]] = true; } dfs(E, -1); bfs(shops); for(int q = 0; q < Q; q++){ int a, b; cin>>a>>b; a--; // eliminiamo l'edge ad indice a pair<int, int> e = edges[a]; // mi serve l'estremo più distante da E int e1 = e.first; int e2 = e.second; bool test1 = inst(e1, e2); int d = test1 ? e2 : e1; if(!inst(d, b)){ cout<<"escaped"<<endl; continue; } ll mn = LLONG_MAX; // devo sfruttare il precalcolo for(int s : shops){ if(inst(d, s)) mn = min(mn, dist[s][b]); } if(mn == LLONG_MAX) cout<<"oo"<<endl; else cout<<mn<<endl; } } int main(){ solve(); return 0; }
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